To solve the given problem, we start with the two equations provided:1. \( \tan \theta = \frac{x \sin \phi}{1 - x \cos \phi} \) 2. \( \tan \phi = \frac{y \sin \theta}{1 - y \cos \theta} \)We need to find the value of \( \frac{x}{...
If tantheta=(xsinphi)/(1-xcosphi) and tanphi=(ysintheta)/(1-ycostheta), then x/y= (A) sinphi/sintheta (B) sintheta/sinphi (C) sinphi/(1-costheta) (D