Blogger:https://blog.baozitraining.org/2019/06/leetcode-solution-290-word-pattern.html Problem Statement Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty wo...
pattern = "abba", str = "dog cat cat fish" should return false. 没有问题,返回的是false,但是放在LeetCode 上提交,提示错误,错误如下: 代码如下: class Solution { public: bool wordPattern(string pattern, string str) { const int len = pattern.length(); char * c = new char[len+1]; strc...
1publicbooleanwordPatternMatch(String pattern,String str){2if(pattern==null||str==null){3returnfalse;4}56Map<Character,String>lookup=newHashMap<>();7Set<String>dup=newHashSet<>();89returnthis.isMatch(pattern,str,lookup,dup);10}1112// DFS recursion to list out all the possibilities13publi...
AI代码解释 publicclassSolution{publicbooleanwordPattern(String pattern,String str){String[]strArr=str.split(" ");char[]patternArr=pattern.toCharArray();if(strArr.length!=patternArr.length)returnfalse;int[]letter=newint[26];int[]index=newint[26];for(int i=0;i<patternArr.length;i++){if(l...
1//Reference:https://leetcode.com/problems/word-pattern/discuss/73402/8-lines-simple-Java2publicbooleanwordPattern(String pattern, String str) {3String[] words = str.split(" ");4if(words.length !=pattern.length())5returnfalse;6Map index =newHashMap();7for(Integer i=0; i<words.length...
str=str.Replace("!","");if(str==pattern)returntrue;elsereturnfalse; } } 第二种解题方法:用字典 publicclassSolution {publicboolWordPattern(stringpattern,stringstr) {string[] values = str.Split('');if(pattern.Length!=values.Length)
1publicclassSolution {2publicbooleanwordPattern(String pattern, String str) {3if(pattern==null|| str==null)returnfalse;4String[] all = str.split(" ");56if(pattern.length() != all.length)returnfalse;7HashMap<Character, String> map =newHashMap<Character, String>();8HashSet<String> set...
Can you solve this real interview question? Word Pattern - Given a pattern and a string s, find if s follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in s. Specific
首发于LeetCode 切换模式写文章 登录/注册290. 单词规律(Word Pattern) Tye 来自专栏 · LeetCode CategoryDifficulty algorithms Easy (40.43%) Tags hash-table Companies dropbox | uber Given a pattern and a string s, find if s follows the same pattern. 给定一种规律pattern 和一个字符串 s ,判断...
:octocat: (Weekly Update) Python / C++11 Solutions of All 1411 LeetCode Problems - LeetCode-Solutions/C++/word-pattern-ii.cpp at master · kemier/LeetCode-Solutions