COBOL INITIALIZE MOVE1 EQUAL ALGOL N/A := = LISP let set2 equal ALGOL didn’t have a special operator for initialization. Rather, you created the variable with the type, and then later used an operator to assign to it. You could do integer x; x := 5;, but you couldn’t do integ...
“There’s no definition for that word.” This demonstrates a significant problem in programming: How do you indicate “no value” for a piece of storage that is uninitialized, or for the result of an operation?
Well, to be fair, maybe it was my dream, but what I saw was a seriously smart guy, who knew the right way to do it, and who had the freedom to do just that. I may be a hack writer now, but I went to school for programming (COBOL on punch cards, thank you very much), ...