|−3x|+5=0 has no soution because absolute values output positives and this equation implies that the absolute value could output a negative. Further: (x+7)2=0 is true for x=−7. √−x−2=0 is true for x=−4, √x−8=0 is true for x=64. |−3x|−4=0 is true...
Which of the following is the solution to the differential equation ()()=-2xy with the initial condition y(1)=4? ( )A. y=e^(x^2) 4-eB. y=e^(-x^2) 4- 1eC. y=4e^(x^2-1)D. y=4e^(-x^2 1)E. y=e^(-x^2 16)D 相关知识点: 试题来源: 解析 D 反馈 收藏 ...
A linear trigonometric equation involving tan(x) has one solution of (3π )4. Which other possible value for x is a solution? () A. - (3π )4 B. (π )4 C. (5π )4 D. (7π )4 相关知识点: 试题来源: 解析 B 反馈 收藏 ...
b^2+b^2+b=0⇒b(2b+1)=0 Since b≠ 0, the second equation implies tha b=-1/2 . Method 1: The quadratic formula yields x1.2 = -(a+12)±√(a+12)2-4-9-25 2-9 The equation has only one solution precisely when the value of the discriminant, (a + 12)2 -900, is 0....
百度试题 结果1 题目Find the solution of the differential equationfor which when x=1. 相关知识点: 试题来源: 解析 2(1+x^2)(1-y^2)=3 反馈 收藏
||x−2|+a|=4 can have four distinct real solutions. Video SolutionText SolutionGenerated By DoubtnutGPT To solve the problem, we need to find the values of a for which the equation ||x−2|+a|=4 can have four distinct real solutions. Let's break this down step by step....
Question: Choose which interval(s) satisfy this inequality: (x-14)(x-11)<0(-\infty ,11)[11,14](11,14)(14,\infty )(-\infty ,11][14,\infty ) 4- ) (11,1 infty) (-\infty,11] [14,\infty)
百度试题 结果1 题目【题目】【题目】Which of the following i sthe solution to the differenti alequation _ wit hth einitial【题目】【题目】【题目】【题目】【题目】 相关知识点: 试题来源: 解析 【解析】 【解析】 反馈 收藏
Question: 2Problem 4) Given the equation y=ax2+4x+24 which has an axis of symmetry of x=12, find the solutions y=ax2+4x+24which has an axis of symmetry of1 There are 2 steps to solve this one.
aMust do with the father counts the mathematics problem? 必须做以父亲计数数学问题? [translate] awhich can be solved for the coecients vi. The third equation is a quadratic equation for v2 that has a real solution if and only if 正在翻译,请等待... [translate] ...