百度试题 结果1 题目The solution of the matrix equation is X=A^(-1)B. 相关知识点: 试题来源: 解析反馈 收藏
a不许考我 Does not have to test me[translate] aThe solution of the first equation is U0(x) = Ax, but we set A = 0 because U0(x) = O(x2). We find also first等式的解答是U0 (x) =轴,但我们设置了A = 0,因为U0 (x) = O (x2)。 我们也find[translate]...
Use the distributive property to simplify both sides of the equation, then add like terms to isolate the variable and find the solution.4(x- 1)=2(x+ 1)4x-4=2x +24x-2x=2 +42x= 6x=3TEST PREP DOCTOR: Students who answeredA may have made a computation error. Students who answ...
What is the solution to the differential equation if x = 1 at t = 0, and dx/dt = 0 at t = 0? ...Question: What is the solution to the differential equation if {eq}x = 1 {/eq} at {eq}t = 0 {/eq}, and {eq}\displayst...
{eq}x + 2.27 = 1.53 {/eq} Linear equation in one variable:The linear equations in one variable are an equation that is expressed in the form of {eq}ax+b = 0 {/eq}, where a and b are two integers and x is a variable and has only one solution.Answer and Explanation...
解析 D Choice D is correct. The value of b^2-4ac determines the nature of roots. From the equation substitute a=1, b=1, and c=1 into the expression. b^2-4ac=1-4=-3. As b^2-4ac is negative, there are no real solutions to the equation.反馈 收藏 ...
Given equation is [(x,y),(z,t)]^(2)=[(0,0),(0,0)] implies [(x,y),(z,t)][(x,y),(z,t)]=[(x^(2)+yz,xy+yt),(zx+tz,zy+t^(2))]=[(0,0),(0,0)] implies x^(2)+yz=0 (1) y(x+t)=0 (2) z(x+t)=0 (3) yz+t^(2)=0 (4) From (1) and (4),...
百度试题 结果1 题目4 The solution(s) to the equation x2 = 5.x is/are x_1=0,x_2=5 相关知识点: 试题来源: 解析 答案见上 反馈 收藏
THE SOLUTION OF x=y=o OF THE EQUATION a/x+b/y=cFirst page of articledoi:10.1111/j.1949-8594.1907.tb01085.xM. O. TrippBlackwell Publishing LtdSchool Science & Mathematics
What is the solution to the equation 5x = 80?Finding the Value of a VariableWhenever we are given equation in a single variable, we must make sure that we transform the equation in such a way that on one side, we have the variable and nothing else and on the other side we have all...