Wait a second. I put thenoexceptkeyword on this function. Certainly that means that any unhandled exception in the function terminates the program, right? Yes, that’s what it means, but your coroutine isn’t the function. The function is the thing that returns asimple_task. And thenoexcept...
Settings SystemAppData TempState If you callSystem.Environment.GetFolderPath(System.Environment.SpecialFolder.Personal)you get a path to a folder with the “AC” Folder. What does AC stand for and what is it’s purpose. I didn’t find any documentation concerning this topic. ...
We’d recommend you to come back if you still have any question or concerns related to Azure DevOps. We will still be here to help you solve issues. Thank you for helping us build a better Azure DevOps. OK, good to know 0 Reconsider 0 Show reactions 0...
What does it mean to the program that a function is declared asnoexcept? Forget what the intent of the programmer is, or could be. Just answer a ‘technical’ question: what does it change in the program from the perspective of run-time behaviour, observable results and the type system?
noexceptThe noexcept operator can now be used to check whether an expression might throw an exception. The noexcept specifier can now be used to specify that a function does not throw exceptions.(C++11) Inline NamespacesA namespace can now be specified as inline to hoist its contents into the...
struct S1 { void f(int); void f(int, int); }; struct S2 { template <class C, void (C::*Function)(int) const> void f() {} }; void f() { S2 s2; s2.f<S1, &S1::f>(); } The current compiler correctly gives an error, because the template parameter type does not match...
Wait a second. I put thenoexceptkeyword on this function. Certainly that means that any unhandled exception in the function terminates the program, right? Yes, that’s what it means, but your coroutine isn’t the function. The function is the thing that returns asimple_task. And thenoexcept...
struct S1 { void f(int); void f(int, int); }; struct S2 { template <class C, void (C::*Function)(int) const> void f() {} }; void f() { S2 s2; s2.f<S1, &S1::f>(); } The current compiler correctly gives an error, because the template parameter type does not match...
struct S1 { void f(int); void f(int, int); }; struct S2 { template <class C, void (C::*Function)(int) const> void f() {} }; void f() { S2 s2; s2.f<S1, &S1::f>(); } The current compiler correctly gives an error, because the template parameter type does not match...
struct S1 { void f(int); void f(int, int); }; struct S2 { template <class C, void (C::*Function)(int) const> void f() {} }; void f() { S2 s2; s2.f<S1, &S1::f>(); } The current compiler correctly gives an error, because the template parameter type does not match...