'void*' is not a pointer-to-object type 错误的含义 'void*' is not a pointer-to-object type 这个错误通常出现在使用某些需要指针指向具体对象类型的C++模板或函数中时,错误地使用了 void* 类型指针。在C++中,void* 是一个通用指针类型,它可以指向任意类型的数据,但由于它本身不指向任何具体的对象类型,因...
问出现"void* is not a pointer-to-object type“错误，但代码在使用XCode时可以完美执行ENStruts has...
Compiler Error: 'void*' is not a pointer-to-object type 下面这个代码是使用void指针存储整型类型的数据,并且void指针被强转为整型指针,并且被解引用。 // C program to dereference the void // pointer to access the value #include <stdio.h> int main() { int a = 10; void* ptr = &a; /...
问C++。错误: void不是指向对象的指针类型ENvoid指针使用规范 ①void指针能够指向随意类型的数据，亦就...
5:6: error: 'void*' is not a pointer-to-object type 6:6: error: 'void*' is not a pointer-to-object type 6:11: error: 'void*' is not a pointer-to-object type In function 'void* foo1(void*)': 11:4: error: 'void*' is not a pointer-to-object type ...
A consequence of this is that sizeof is also allowed on void and on function types, and returns 1. The option -Wpointer-arith requests a warning if these extensions are used. 意思是,在 GNU C中,指向 void 指针和指向函数的指针支持加法和减法操作。这是通过将 void 或函数的大小视为1来实现的...
void* b=a; voidfoo(){ char* c=b; } ISO C will accept this usage of pointer to void being assigned to a pointer to object type. C ++ will not. 但是为什么operator new()会返回void*且不用显式转换为T*就能赋值给T*呢? global scope的operator new基本原型为: ...
A consequence of this is thatsizeofis also allowed onvoidand on function types, and returns 1. The option -Wpointer-arith requests a warning if these extensions are used. 意思是,在 GNU C中,指向void指针和指向函数的指针支持加法和减法操作。这是通过将void或函数的大小视为1来实现的。 因此,size...
Since void is an incomplete type, it is not an object type. Therefore it is not a valid operand to an addition operation. Therefore you cannot perform pointer arithmetic on a void pointer. Notes Originally, it was thought that void* arithmetic was permitted, because of these sections of the...
...以下是一个例子:int a = 10;void* p = &a; // p 是一个 void*,指向 int 类型的数据void** pp = &p; // pp 是一个 void**,指向 p在这个例子中...总结中的进一步思考理解 void,void*,和 void** 是深入掌握 C 语言的关键,它们为编程提供了强大的灵活性,同时也带来了复杂性。