1. 解释“pointer of type 'void *' used in arithmetic”这个警告的含义 这个警告信息意味着在C或C++程序中,尝试对类型为void *的指针进行了算术运算。在C和C++中,void *是一个通用指针类型,表示一个通用指针,它不指向任何特定类型的数据。由于void *没有类型信息,编译器无法确定指针算术运算的单位大小(例如,...
对void* 类型的指针进行加减运算的时候,这是不安全的,因为编译器并不知道你指针的单元是多少,需要移动多长的距离。作为扩展,大部分编译器都允许给void 指针做算术运算。
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可以初始化，但是printf那句还需要写成*((int*)a)这样编译器才知道这个地方是需要用整形指针来求值。
The exception to this rule is the pointer to void (i.e., void *), which is a generic pointer capable of representing any pointer type. All pointer types can be assigned to a pointer of type void * without casting. However, a pointer of type void * cannot be assigned directly to a ...
指针数组: Type *array[] 数组指针: Type (*array)[]指针函数: Type *function(void)函数指针: Type (*function)(void)函数指针数组: Type (*array[])(void)今天是20200305指针数组,数组指针,指针函数.函数指针,函数指针数组,指针的指针,多级指针你值得拥有 ...
void main(void) { char *ch; char b = ’A’; ch = &b; /* assign address of b to ch */ printf(“%c”, *ch); } In the above example, b: value of b, which is ‘A’ &b: address of b, i.e., 36624 ch: value of ch, which is 36624 ...
When running make I get the following errors: ././files/tf_tensor_helper.cc:43:46: error: arithmetic on a pointer to void *(char *)(buffer_data_pointer+i) = file_string[i]; ././files/tf_tensor_helper.cc:52:56: error: arithmetic on a poin...
Since void is an incomplete type, it is not an object type. Therefore it is not a valid operand to an addition operation. Therefore you cannot perform pointer arithmetic on a void pointer. Notes Originally, it was thought that void* arithmetic was permitted, because of these sections of the...
In an unsafe context, a type may be a pointer type, a value type, or a reference type. A pointer type declaration takes one of the following forms:复制 type* identifier; void* identifier; //allowed but not recommended Any of the following types may be a pointer type:...