Example 1: Find the vertex of y = 3x2 - 6x + 1. Solution: To find: The vertex of the given equation (parabola). Comparing the given equation with y = ax2 + bx + c, we get a = 3, b = -6, c = 1. Then the discriminant is, D = b2 - 4ac = (-6)2 - 4(3)(1) =...
Let f(x)=3x2−6x+k, where k is a constant. If the y−coordinate of the vertex of the gr
Class 12MATHSPARABOLA Similar Questions Write the distance between the vertex and focus of the parabolay2+6y+2x+5=0. View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
Using the standard equation of y=ax^2+bx+c, find the x value of the vertex point by plugging the a and b coefficients into the formula x= -b/2a. For example: y=3x^2+6x+8 x= -6/(2*3) = -6/6 = -1 Step 2 Substitute the found value of x into the original equation to f...
Answer to: Find the coordinates of the vertex of y = -3x2 - 6x + 2. By signing up, you'll get thousands of step-by-step solutions to your homework...
What is the vertex form of the function y = x^2 - 6x + 4? a) y = (x - 3)^2 - 6 b) y = (x - 3)^2 - 5 c) y = (x - 3)^2 + 4 d) y = (x - 3)^2 + 13 What are the coordinates of the vertex of the function f(x) = x^2 + 10x - 3: ...
As complex manifold, they are isomorphic, therefore we can treat C/Λ as a variety and construction a vertex algebra sheaf on it.doi:CNKI:SUN:SXJK.0.2016-01-006SUN Yuan-yuanDepartment of Publiccnki数学季刊(英文版)
The vertex of the parabola y^2+6x-2y+13=0 is 01:48 If the parabola y^2=4a x\ passes through the point (3,2) then find th... 01:29 Find the value of P such that the vertex of y=x^2+2p x+13 is 4 units a... 01:52 The length of the latusrectum of the parbola whose...
Start with the standard form of the parabolic equation; for example, y = (x + 3)² + 4. When plotted on a graph, the parabola will have a vertex of 3, 4. Step 2 Expand the polynomial within the parentheses: (x+3)(x+3). Add the 4 back into the equation; you will now have...
You needy = a(x - h)2+ kthe vertex form of the parabola, withvertex at point (h, k). If the vertex is (4,-1) the equation becomesy = a(x - 4)2- 1 So now we need to find a, by using the given y intercept (0,15), so we substitute the point values to get ...