( y=-x^2+3x-2) 相关知识点: 试题来源: 解析 Rewrite the equation in vertex form. ( y=-((x-3/2))^2+1/4) Use the vertex form, ( y=a((x-h))^2+k), to determine the values of ( a), ( h), and ( k). ( a=-1) ( h=3/2) ( k=1/4) Find the vertex( (h,k...
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Find the Vertex y=-2x^2+4x+5${\displaystyle y=-2{x}^{2}+4x+5}$ 答案 Rewrite the equation in vertex form.${\displaystyle y=-2{(x-1)}^{2}+7}$Use the vertex form, ${\displaystyle y=a{(x-h)}^{2}+k}$, to determine the values of ${\displaystyle a}$, ${\displaystyle...
Enter a problem...Algebra ExamplesPopular ProblemsAlgebraFind the Vertex y=(x-4)^2-3Step 1 Use the vertex form, , to determine the values of , , and .Step 2 Find the vertex .Step 3
Answer to: Write the function in vertex form. y = - x^2 - 3x - 6 \\y = \boxed{\space} By signing up, you'll get thousands of step-by-step...
3、作图后,观察二次函数y=x2的图象像什么,有什么特点? 4、得出结论:二次函数y=x2的图象形如物体抛射时所经过的路线,我们把这样的曲线通常叫做抛物线(parabola),它是轴对称图形,y轴是它的对称轴,抛物线与它的对称轴的交点叫做抛物线的顶点(vertex ). 5.展示生活中的抛物线图片 掌握二次函数图象的画法。 让学...
The vertex and focus of parabola (y-2)^(2) = -4(x-4) are 02:15 The equation of the latus rectum of the parabola x^(2)-12x-8y+52=0 is 03:50 The ends of the latus rectum of the parabola (x-2)^(2)=-6(y+1) are 04:45 The focal distance of the point (9,6) on the...
Find the vertex and (align*)x(align*) -intercepts of the function (align*)y=(x-4)^2-9(align*) .相关知识点: 试题来源: 解析 Vertex: (align*)(4,-9)(align*) ; x-intercepts: (align*)(1,0)(align*) and (align*)(7,0)(align*) ...
Step by step video, text & image solution for On the portion of the line x/3+y/4=1 intercepted between the axes a square is constructed away from the origin. Coordinates of the vertex of square which is farthest from origin is by Maths experts to help you in doubts & scoring excellent...
Find theaxis of symmetryby finding thelinethat passes through thevertexand thefocus. x=34x=34 y=2x2−3x+4y=2x2-3x+4 ( ) | [ ] √ ≥ 7 8 9 ≤ 4