Declare Function CreateFile Lib "kernel32" Alias "CreateFileA" (ByVal lpFileName As String, ByVal dwDesiredAccess As Long, ByVal dwShareMode As Long, lpSecurityAttributes As SECURITY_ATTRIBUTES, ByVal dwCreationDisposition As Long, ByVal dwFlagsAndAttributes As Long, ByVal hTemplateFile As Long)...
Workbooks.Open(FileName, UpdateLinks, ReadOnly, Format, Password, WriteResPassword, IgnoreReadOnlyRecommended, Origin, Delimiter, Editable, Notify, Converter, AddToMru, Local, CorruptLoad) 其中FileName是必选的参数,表示要打开的工作簿名,如果没有指定路径,则代表当前路径。另外14个是可选参数,除了密码参...
Sub FileBackUp() ThisWorkbook.SaveCopyAs Filename:=ThisWorkbook.Path & _ "" & Format(Date, "mm-dd-yy") & " " & _ ThisWorkbook.name End Sub 这是最有用的宏之一,可以帮助您保存当前工作簿的备份文件。它将备份文件保存在保存当前文件的同一目录中,并且还将添加带有文件名的当前日期。 49. 一次关...
问引用VBA ( GetOpenFilename宏)EN函数作用：计算结构体成员的偏移，有些自有代码里也会手写这样的代码...
GetOpenFilename 是VBA 中用于显示文件选择对话框的方法,允许用户选择一个或多个文件,并返回文件的路径。它不会实际打开文件,只是返回用户的选择。其基本语法如下: Application.GetOpenFilename([FileFilter], [FilterIndex], [Title], [MultiSelect]) FileFilter: 可选。指定文件类型过滤器,如 "Excel Files (*.xl...
workbookPath = fso.GetAbsolutePathName(ThisWorkbook.FullName) ' 显示工作簿路径 MsgBox "工作簿路径:" & workbookPath ' 释放Filesystemobject对象 Set fso = Nothing End Sub 上述代码中,首先创建了一个Filesystemobject对象,然后使用GetAbsolutePathName方法获取当前工作簿的绝对路径,并将路径存储在workbookPath变量中。最...
Example 4 – Applying the GetOpenFilename Method to Open a Workbook from a Path in Excel Steps: Follow the steps described in Example 1. Enter the following Code in Module4. Sub Open_WB() Dim Dialog_Box_File As String Dialog_Box_File = Application.GetOpenFilename() Workbooks.Open (Dial...
The File Exists. VBA中的Dir函数,可以实现类似的功能,用到的主要代码为:FileName = Dir(Path)。 4.2 基于给定路径,创建新文件夹 Sub CreateFolder() Dim MyFSO As FileSystemObject Set MyFSO = New FileSystemObject If MyFSO.FolderExists('C:\a\f') Then ...
Public Function MD5File(ByVal FileName As String) As Byte() Const BUFFERSIZE As Long = 1024& * 512 ' 缓冲区 512KB Dim DataBuff() As Byte Dim lFileSize As Long Dim iFn As Long On Error GoTo E_Handle_MD5 If (Len(Dir$(FileName)) = 0) Then Err.Raise 5 '文件不存在 ...
获取路径public void showURL() throws IOException { // 第一种:获取类加载的根路径D:\git\daotie\daotie\target\classes File f = new File(this.getClass().getResource("/").getPath()); System.out.p java获取用户桌面 System git desktop ...