在B列中我们利用自定义函数NZNumToLetter（），输出的结果：二根据字母给出列的数值 我们看一下这个工具的应用界面，如下图：点击后代码会运行，程序中我给出的是”AG”列，要求求出这列的列数值，结果如下：Ø代码见程序文件：VBA_ConvertColumnNumberToLetter.xlsm ...
点击后代码会运行,程序中我给出的是”AG”列,要求求出这列的列数值,结果如下: 代码见程序文件:VBA_ConvertColumnNumberToLetter.xlsm
点击后代码会运行,程序中我给出的是”AG”列,要求求出这列的列数值,结果如下: Ø代码见程序文件:VBA_ConvertColumnNumberToLetter.xlsm
III.Excel Formula to Get Column Letter from Number Get vba code & Excel formula to get Column letter from column number, in here. For example, If you pass ‘1’ to the function in this code, it will return as “A”. Similarly “B” for 2, “C” for 3 & so on. ...
Function ColIntToLetter(intCol As Integer) As String '' Dim intPart As Integer Dim intRemainder As Integer If intCol > 255 Or intCol <= 0 Then MsgBox ("The Wrong Column Number: " & CStr(intCol)) Exit Function End If intPart = intCol \ 26 intRemainder = intCol Mod 26 If intPart...
Get Excel VBA code to convert Column Letter to number. The Formula & Excel vba code will get column alphabet letter & return the Column number as value.
'### Function ColIntToLetter(intCol As Integer) As String '' Dim intPart As Integer Dim intRemainder As Integer If intCol > 255 Or intCol <= 0 Then MsgBox ("The Wrong Column Number: " & CStr(intCol)) Exit Function End If intPart = intCol \ 26 intRemainder = intCol Mod 26 If...
If numOrLetter > 702 Then MsgBox '只允许输入小于“703”的数字。' Exit Function End If If numOrLetter > 26 Then idx = 26 For i = 0 To 25 For j = 0 To 25 idx = idx + 1 If idx = numOrLetter Then excelColumn_numLetter_interchange = letterArray(i) & letterArray(j) ...
excelColumn_numLetter_interchange = letterArray(numOrLetter - 1) End If Else numOrLetter = UCase(numOrLetter) '转换为大写 If Len(numOrLetter) > 1 And Len(numOrLetter) < 3 Then idx = 26 For i = 0 To 25 For j = 0 To 25 ...
1、返回 Column 英文字: Function ColLetter(ColNumber As Integer ) As String On Error GoTo Errorhandler ColLetter = Left (Cells( 1 , ColNumber).Address( 0 , 0 ), 1 - (ColNumber > 26 )) Exit Function Errorhandler: MsgBox " Error encountered, please re-enter " ...