import java.util.Stack; class Solution { public boolean isValid(String s) { Stack<Character> stack_match = new Stack<Character>(); for(int i=0;i<s.length();i++){ if(s.charAt(i)=='(' || s.charAt(i)=='[' || s.charAt(i)=='{'){ stack_match.push(s.charAt(i)); }else...
Leetcode20 - Valid Parentheses Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not. 第一反...
3.Solutions: 1/**2* Created by sheepcore on 2019-05-073*/45classSolution {6publicbooleanisValid(String s) {7Stack<Character> stack =newStack<Character>();89for(charch : s.toCharArray()){10switch(ch){11case'(':12case'{':13case'[': stack.push(ch);break;14case')':15if(!stack....
【因为这有三种括号,三个之间的嵌套比较复杂,所以不能简单地使用整形int作为判断(左括号++,右括号--),例如“([)]”这要是使用int那么就会判断正确。】 算法——利用一个栈,如果是左括号则直接放入,如果是右括号,pop栈顶看是否为对应左括号,否则return false;最后检查栈是否为空。 我的代码: 1publicbooleanis...
An input string is valid if: 如果输入字符串有效 Open brackets must be closed by the same type of brackets. 必须使用相同类型的括号关闭左括号 Open brackets must be closed in the correct order. 必须用正确的顺序关闭左括号 Note that an empty string is also considered valid. ...
not. 原题链接:https://oj.leetcode.com/problems/valid-parentheses/ 题目:给定一个仅包括'(',')','{','}','['和']' 的字符串,检測输入的串是否合法。括号是否配对。 思路:使用一个栈。遇到左括号则压入。遇到右括号则与左括号检測是否匹配,不匹配即false,弹出顶元素,循环。
https://leetcode-cn.com/problems/valid-parentheses/ 练习使用JavaScript解答 /** * @param {string} s * @return {boolean} */ var isValid = function(s) { if(s == "") return true; var arr = []; var stu = { '}':'{', ...
Can you solve this real interview question? Valid Parentheses - Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: 1. Open brackets must be closed by th
package leetcode._20;import java.util.Stack;publicclassSolution{publicbooleanisValid(String s){Stack<Character>stack=newStack<>();for(inti=0;i<s.length();i++){charc=s.charAt(i);if(c=='('||c=='['||c=='{'){stack.push(c);}else{if(stack.isEmpty()){returnfalse;}chartop=stack...
Java publicclassSolution{publicbooleanisValid(String s){if(s==null||s.length()==0)returnfalse;Stack<Character>parentheses=new Stack<Character>();for(int i=0;i<s.length();i++){char c=s.charAt(i);if(c=='('||c=='['||c=='{')parentheses.push(c);else{if(parentheses.empty())re...