Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis'('must have a corresponding right parenthesis')'. Any right parenthesis')'must h...
Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis '(' must have a corresponding right parenthesis ')'. Any right parenthesis ')'...
678. Valid Parenthesis String FindTabBarSize Given a stringscontaining only three types of characters:'(',')'and'*', returntrueifsisvalid. The following rules define avalidstring: Any left parenthesis'('must have a corresponding right parenthesis')'. Any right parenthesis')'must have a corresp...
Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis'('must have a corresponding right parenthesis')'. Any right parenthesis')'must h...
Leetcode 678. Valid Parenthesis String 题目链接:Valid Parenthesis String 题目大意:给定一个只由左括号,右括号,星号组成的字符串,星号可以当作左括号,右括号或者空,问该字符串是否是匹配的 题目思路:这题的解法十分多,比如我们可以使用两个栈,分别记录左括号和星号的位置,当遇到右括号时,有左括号就弹出左括号...
Can you solve this real interview question? Valid Parenthesis String - Given a string s containing only three types of characters: '(', ')' and '*', return true if s is valid. The following rules define a valid string: * Any left parenthesis '(' must
code class Solution { public: bool checkValidString(string s) { int cmin=0,cmax=0; for(char c : s) { if(c=='(') { cmin++; cmax++; } else if(c==')') { cmin--; cmax--; } else if(c=='*') { cmax++; cmin--; } if(cmax<0) return false; cmin=max(0,cmin);...
class Solution { public: bool checkValidString(string s) { int n = s.length(); vector<vector<bool>> f(n + 1, vector<bool>(n + 1, false)); f[0][0] = true; for (int i = 1; i <= n; i++) { char c = s[i - 1]; for (int j = 0; j <= i; j++) { if (c...
Valid Parenthesis String 题目大意:给定一个只由左括号,右括号,星号组成的字符串,星号可以当作左括号,右括号或者空,问该字符串是否是匹配的 题目思路:这题的解法十分多,比如我们可以使用两个栈,分别记录左括号和星号的位置,当遇到右括号时,有左括号就弹出左括号,没有就弹出星号去匹配。但是Leetcode的...
'*'could be treated as a single right parenthesis')'or a single left parenthesis'('or an empty string"". Example 1: Input: s = "()"Output: true Example 2: Input: s = "(*)"Output: true Example 3: Input: s = "(*))"Output: true ...