代码(Python3) class Solution: def validPalindrome(self, s: str) -> bool: # 定义左指针 l ,初始化为 0 l: int = 0 # 定义右指针 r ,初始化为 s.length - 1 r: int = len(s) - 1 # 当还有字符需要比较时,继续处理 while l < r: # 如果 s[l] 和 s[r] 不相等,则需要删除字符 if...
代码如下: 1classSolution(object):23defisPalindrome(self, s, left, right, flag):4whileleft <right:5ifs[left] ==s[right]:6left += 17right -= 18else:9ifflag == 1:10returnFalse11flag = 112return(self.isPalindrome(s, left+1, right, flag)or13self.isPalindrome(s, left, right-1, f...
1、注意空字符串的处理; 2、注意是alphanumeric字符; 3、字符串添加字符直接用+就可以; 1classSolution:2#@param s, a string3#@return a boolean4defisPalindrome(self, s):5ret =False6s =s.lower()7ss =""8foriins:9ifi.isalnum():10ss +=i11h =012e = len(ss)-113while(h<e):14if(ss...
leetcode.cn/problems/Xl 解题思路 先全部转小写字母(题目要求忽略大小写)然后先去除除了字母和数字的字符,首尾依次比较 解题方法 俺这版 class Solution { public static boolean isPalindrome(String s) { String s1 = s.toLowerCase().replaceAll("[^a-z|0-9]", ""); int length = s1.length(); fo...
[Leetcode][python]Valid Palindrome/验证回文串 题目大意 判断一个字符串是否是回文字符串,只考虑字母和数字,并且忽略大小写。 注意点: 空字符串在这里也定义为回文串 解题思路 去掉除了数字和字母之外的字符isalnum() 都改为小写 将数组(字符串)反过来,判断是否相等...
LeetCode-Valid Palindrome II Description: Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: AI检测代码解析 Input: "aba" Output: True 1. 2. Example 2: AI检测代码解析...
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LeetCode 125:Valid Palindrome(有效回文) Q:Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. Note: For the purpose of this problem, we define empty string as valid palindrome.
Python class Solution: # @param {string} s A string # @return {boolean} Whether the string is a valid palindrome def isPalindrome(self, s): if not s: return True l, r = 0, len(s) - 1 while l < r: # find left alphanumeric character if not s[l].isal...
Can you solve this real interview question? Valid Palindrome - A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric c