publicbooleanvalidPalindrome(String s){// 使用双指针intleft=0;intright=s.length()-1;while(left < right) {// 如果左右指针所在的字符不相等,那就删掉右边的或者删掉左边的字符,再判断if(s.charAt(left) != s.charAt(right)) {returnisPalindrome(s, left, right-1) || isPalindrome(s, left+1, ...
3.1 Java实现 publicclassSolution{intpos=0;publicbooleanvalidPalindrome(String s){booleanvalid=isPalindrome(s);if(!valid) {intleft=pos;intright=s.length() - pos;booleanret1=isPalindrome(s.substring(left +1, right));booleanret2=isPalindrome(s.substring(left, right -1)); valid = ret1 || ...
LeetCode-Valid Palindrome II Description: Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True 1. 2. Example 2: Input: "abca" Output: True Explanation: You could delete the character 'c'....
但是需要遍历两次,每次删除的是前面一个元素还是后面一个元素。 classSolution(object):defvalidPalindrome(self,s):""":type s: str:rtype: bool"""i,j=0,len(s)-1count1=0whilei<=j:ifs[i]==s[j]:i+=1j-=1elifj-1>=0ands[j-1]==s[i]:j-=1count1+=1elifi+1<len(s)ands[i+1]==...
[LeetCode] Valid Palindrome II 验证回文字符串之二 Given a non-empty strings, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: Input: "aba" Output: True Example 2: Input: "abca" Output: True...
Valid Palindrome·有效回文 秦她的菜 吉利 程序员题目描述 英文版描述 A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and ...
For the purpose of this problem, we define empty string as valid palindrome. 思路分析: 将字符串中的非数字字母字符跳过,大写全部转小写,然后从字符串两头向中间逼近,逐一进行比较。 C++参考示例: 代码语言:javascript 复制 classSolution{private:boolisAlphanumeric(char&ch){if(ch>='A'&&ch<='Z'){ch+...
For the purpose of this problem, we define empty string as valid palindrome. [ 解法1:] 先把有效的字母、数字准备好,然后遍历目标字符串,有效的字符放入buffer。 再比較buffer中的字符串和反转后的字符串,假设同样那就是回文。否则不是回文。 点评:这个解法能够被系统accept,但调用了太多api,性能一般。
LeetCode 132. Palindrome Partitioning II LeetCode 526. Beautiful Arrangement LeetCode 486. Predict the Winner 至此,递归/回溯/DFS和动态规划两大难点搞完了,剩下的就是一下小而精的算法和数据结构,比如二分、单调栈、单调队列(滑动窗口)、栈、队列、哈希、图论(很少)、贪心、数学、设计等,有空再选题分类叭...
1.3 Search in Rotated Sorted Array II 1.4 Median of Two Sorted Arrays 1.5 Longest Consecutive Sequence 1.6 Two Sum 1.7 Valid Sudoku 1.8 Trapping Rain Water 1.9 Swap Nodes in Pairs 1.10 Reverse Nodes in k-Group 2. 字符串 2.1 Valid Palindrome 2.2 Implement strStr() 3.3 String to Integer (at...