leetcode题解:Valid Palindrome(判断回文) 题目: Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example, "A man, a plan, a canal: Panama"is a palindrome. "race a car"isnota palindrome. Note: Have you consider that the stri...
* 方式1:翻转字符串 */publicstaticbooleanvalindPalindrome(Stringstr){//去掉非字母和数字的字符Stringstr1 = str.replaceAll("[^a-zA-Z0-9]","");//字母全转为小写Stringstr2 = str1.toLowerCase();//翻转字符串Stringstr3 =newStringBuilder(str2).reverse().toString();//对比翻转前与翻转后的字符...
is_palindrome(s, l + 1, r) or Solution.is_palindrome(s, l, r - 1) # 此时 s[l] 和 s[r] 相等,可以继续处理。 #将 l 向右移动一位 l += 1 #将 r 向左移动一位 r -= 1 # 此时说明 s 本身就是回文,直接返回 True return True @staticmethod def is_palindrome(s: str, l: int,...
【LeetCode】5. Valid Palindrome·有效回文 秦她的菜 吉利 程序员 来自专栏 · Leetcode刷题笔记 题目描述 英文版描述 A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. ...
LeetCode-Valid Palindrome II Description: Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome. Example 1: AI检测代码解析 Input: "aba" Output: True 1. 2. Example 2: AI检测代码解析...
题目链接:https://leetcode.com/problems/valid-palindrome/ 题目: Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example, "A man, a plan, a canal: Panama"is a palindrome. ...
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LeetCode 125:Valid Palindrome(有效回文) Q:Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. Note: For the purpose of this problem, we define empty string as valid palindrome.
1. Valid PalindromeII Given a strings, returntrueif thescan be palindrome after deletingat most onecharacter from it. Example 1: Input: s = "aba" Output: true Example 2: Input:s="abca"Output:trueExplanation:You coulddeletethe character'c'. ...
public class ValidPalindrome { public static boolean isValidPalindrome(String s){ if(s==null||s.length()==0) return false; s = s.replaceAll(“[^a-zA-Z0-9]”, “”).toLowerCase(); System.out.println(s); for(int i = 0; i < s.length() ; i++){ ...