这道题目和Unique Path 基本一样。之前我们是给start point 1的值,然后遍历matrix,拿left 和 top的值加起来。那么这题,1被用了,代表障碍物。那我们就用-1。首先来分析一下,如果起点或者终点都是1的话,那么就无路可走,直接return 0就可以。剩下的情况,对于每一个点,如果它是障碍物,就直接跳过;如果不是,...
classSolution {public:intuniquePathsWithObstacles(vector<vector<int>>&obstacleGrid) {intm =obstacleGrid.size();intn = obstacleGrid[0].size(); vector<vector<int> > a(m, vector<int>(n));intpath1,path2,path=0;intj;for(inti =0; i < m; i++) {if(obstacleGrid[i][0] ==1) {for...
https://leetcode.com/problems/unique-paths-ii/ 题目: Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How many unique paths would there be? 1and0 For example, There is one obstacle in the middle of a 3x3 grid as illustrated below. [ [0,0,0],...
整体思路与LeetCode_Array_62. Unique Paths (C++)差不多,只不过有以下几点需要注意: 这次的输入为数组,故可以在输入矩阵的基础上进行赋值,从而使空间复杂度为O(1),然而Java语言可以通过,C++会产生溢出错误,因此,使用C++解决此题需重新声明类型为unsigned int 或 long类型的数组,方可进行下一步; ...
Unique Paths II Medium Minimum Path Sum Medium Dungeon Game Hard Minimum Path Cost in a Grid Medium Minimum Cost Homecoming of a Robot in a Grid Medium Number of Ways to Reach a Position After Exactly k Steps Medium Paths in Matrix Whose Sum Is Divisible by K Hard Discussion (189) ...
Unique Path问题指在m×n的网格中,从左上角到右下角寻找仅通过向右或向下移动的路径总数,其核心解法包括动态规划、数学组合公式和记
测试地址: https://leetcode.com/problems/unique-paths/description/ beat 100%. """ class Solution(object): def uniquePaths(self, m, n): """ :type m: int :type n: int :rtype: int """ _map = [[0 for _ in range(m)] for _ in range(n)] # _map[0][0] = 1 for i in ...
1129-Shortest-Path-with-Alternating-Colors 1133-Largest-Unique-Number 1134-Armstrong-Number 1135-Connecting-Cities-With-Minimum-Cost 1136-Parallel-Courses 1140-Stone-Game-II .gitignore qrcode.png readme.md Breadcrumbs Play-Leetcode /0980-Unique-Paths-III / cpp-0980/ Director...
Unique Path 邪恶总督 旅居荷兰 从事科技行业 欢迎交友 来自专栏 · 算法,数据结构沉思录 A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach ...
2019-12-25 11:28 −文件目录 引入文件 use think\facade\App; require_once App::getRootPath().'/extend/PHPExcel/PHPExcel.php'; 报... 潇潇六月雨 0 1356 thinkphp5 二维码生成 composer 2019-12-20 15:00 −进入extend文件夹 composer require endroid/qrcode 2.将二维码生成封装为服务 QrcodeServe...