Example 1: Input:[[1,0,0,0],[0,0,0,0],[0,0,2,-1]] Output:2 Explanation: We have the following two paths: 1. (0,0),(0,1),(0,2),(0,3),(1,3),(1,2),(1,1),(1,0),(2,0),(2,1),(2,2) 2. (0,0),(1,0),(2,0),(2,1),(1,1),(0,1),(0,2),(...
AC代码: classSolution {intcount = 0;intans =0;intdirx[] = {0,0,1,-1};intdiry[] = {1,-1,0,0};publicintuniquePathsIII(int[][] grid) {if(grid.length==0 || grid==null)return0;for(inti=0;i<grid.length;i++){for(intj=0;j<grid[0].length;j++){if(grid[i][j]==0){...
func uniquePaths(m int, n int) int { // dp[j] 表示从 (0, 0) 到 (i - 1, j - 1) 的不同路径数,初始化均为 0 。 // 这里使用了一维数组 + 临时变量的优化,能将空间复杂度从 O(mn) 降到 O(n) 。 dp := make([]int, n + 1) // 为了方便后续获得 dp[1][1] 为 1 ,这...
Given the two integers m and n, return the number of possible unique paths that the robot can take to reach the bottom-right corner.The test cases are generated so that the answer will be less than or equal to 2 * 109.Example 1:Input: m = 3, n = 7 Output: 28 ...
class Solution { public int uniquePaths(int m, int n) { // 定义dp数组,数组中的值代表到达该位置的路径数目 int[][] dp = new int[m][n]; // 初始化第一行&第一列数值,因为只能向下和向右,所以值默认为1 for(int i = 0; i < m; i++){ dp[i][0] = 1; } for(int j = 0; j...
https://leetcode.com/problems/count-unique-characters-of-all-substrings-of-a-given-string/ https://leetcode.com/problems/fruit-into-baskets/ https://leetcode.com/problems/minimum-number-of-k-consecutive-bit-flips/ https://leetcode.com/problems/longest-substring-without-repeating-characters/ ...
63.Unique Paths II A robot is located at the top-left corner of amxngrid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram be...
Unique Paths II -- LeetCode 原题链接:http://oj.leetcode.com/problems/unique-paths-ii/ 这道题跟Unique Paths非常类似,只是这道题给机器人加了障碍,不是每次都有两个选择(向右,向下)了。因为有了这个条件,所以Unique Paths中最后一个直接求组合的方法就不适用了,这里最好的解法就是用动态规划了。递推...
Path Sum III Swift Easy O(n^2) O(1) Binary Tree Paths Swift Easy O(n) O(n) Binary Tree Maximum Path Sum Swift Hard O(n) O(1) House Robber III Swift Medium O(n) O(1) Unique Binary Search Trees Swift Medium O(n^2) O(n) Recover Binary Search Tree Swift Hard O(n) O(1)...
980 Unique Paths III Solution Hard Backtracking, DFS 979 Distribute Coins in Binary Tree Solution Medium Recursion 977 Squares of a Sorted Array Solution Easy Array 976 Largest Perimeter Triangle Solution Easy Math Array 974 Subarray Sums Divisible by K Solution Medium Array 973 K Closest Points to...