[leetcode] Unique Paths 从二维grid中找出所有的unique paths 原题:https://leetcode.com/problems/unique-paths/#/description 就是给了一个n*m的矩阵。从top-left顶点往bottom-right终点走。每次只能往bottom,或者往right走。(还不算太可怜,每次还有两种选择。往往我们只有一种选择。)。 目标是:找出unique pat...
func uniquePathsWithObstacles(obstacleGrid [][]int) int { m, n := len(obstacleGrid), len(obstacleGrid[0]) // dp[i][j] 表示从 (0, 0) 到 (i - 1, j - 1) 的不同路径数, // 初始化均为 0 dp := make([][]int, m + 1) for i := 0; i <= m; i++ { dp[i] = ma...
A robot is located at the top-left corner of amxngrid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below). How many poss...
https://leetcode.com/problems/unique-paths/ 题目: A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the gr...
The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below). How many possible unique paths are there?Above is a 7 x 3 grid. How many possible unique paths are there? Note: m and n will be at most 100....
63.Unique Paths II A robot is located at the top-left corner of amxngrid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram be...
62. Unique Paths Medium Topics Companies There is a robot on an m x n grid. The robot is initially located at the top-left corner (i.e., grid[0][0]). The robot tries to move to the bottom-right corner (i.e., grid[m - 1][n - 1]). The robot can only move either down...
思路跟Unique Paths是一样的,只是要分类讨论一下障碍的情况,假设当前格子是障碍,那么到达该格子的路径数目是0。由于无法到达,假设是普通格子,那么由左边和右边的格子相加。 AC源代码 class Solution(object): def uniquePathsWithObstacles(self, obstacleGrid): ...
public int uniquePathsWithObstacles(int[][] obstacleGrid) { if(obstacleGrid == null || obstacleGrid.length==0 || obstacleGrid[0].length==0) return 0; int[] res = new int[obstacleGrid[0].length]; res[0] = 1; for(int i=0;i<obstacleGrid.length;i++) ...
Find the list of grid coordinates where water can flow to both the Pacific and Atlantic ocean. Note: The order of returned grid coordinates does not matter. Both m and n are less than 150. Example: 代码语言:javascript 代码运行次数:0 运行 复制 Given the following 5x5 matrix: Paci...