https://leetcode-cn.com/problems/unique-number-of-occurrences/耗时解题:22 min 题解:4 min题意给你一个整数数组 arr,请你帮忙统计数组中每个数的出现次数。如果每个数的出现次数都是独一无二的,就返回 true;否则返回 false。思路两个哈希表,一个用来离散统计出现次数,第二个测试出现次数是否独一无二。
LeetCode.1207-唯一的元素出现次数(Unique Number of Occurrences) 这是小川的第419次更新,第452篇原创 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第269题(顺位题号是1207)。给定一个整数数组arr,当且仅当该数组中每个元素的出现次数唯一时,返回true。 例如: 输入:arr = [1,2,2,1,1,3] 输出:...
今天介绍的是LeetCode算法题中Easy级别的第269题(顺位题号是1207)。给定一个整数数组arr,当且仅当该数组中每个元素的出现次数唯一时,返回true。 例如: 输入:arr = [1,2,2,1,1,3] 输出:true 说明:值1出现3次,值2出现2次,值3出现1次。没有两个值出现的次数相同。 输入:arr = [1,2] 输出:false 输...
Given an array of integersarr, write a function that returnstrueif and only if the number of occurrences of each value in the array is unique. Example 1: Input: arr = [1,2,2,1,1,3] Output: true Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values ...
Can you solve this real interview question? Unique Number of Occurrences - Given an array of integers arr, return true if the number of occurrences of each value in the array is unique or false otherwise. Example 1: Input: arr = [1,2,2,1,1,3] Outpu
Output: true Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences. 1. 2. 3. Example 2: Input: arr = [1,2] Output: false 1. 2. Example 3: Input: arr = [-3,0,1,-3,1,1,1,-3,10,0] ...
1207. Unique Number of Occurrences* https://leetcode.com/problems/unique-number-of-occurrences/ 题目描述 Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is...
2019-12-13 22:36 −Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0... Zhentiw 0 175 LeetCode.1207-唯一的元素出现次数(Unique Number of Occurrences) ...
2019-12-13 22:36 −Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0... Zhentiw 0 174 LeetCode.1207-唯一的元素出现次数(Unique Number of Occurrences) ...
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