https://leetcode.com/explore/challenge/card/30-day-leetcoding-challenge/531/week-4/3313/leetcode.com/explore/challenge/card/30-day-leetcoding-challenge/531/week-4/3313/ You have a queue of integers, you need to retrieve the first unique integer in the queue. Implement the FirstUnique ...
} voidadd(intvalue) { if(cnt[value]>1)return; q.push(value); cnt[value]++; } }; /** * Your FirstUnique object will be instantiated and called as such: * FirstUnique* obj = new FirstUnique(nums); * int param_1 = obj->showFirstUnique(); * obj->add(value); */ 1. 2. 3...
这样在返回unique value的时候,时间上会省很多。 时间O(n),虽然返回unique的动作是O(1)但是add()函数在极端情况下也会很费时间 空间O(n) Java实现 1classFirstUnique {2Set<Integer> unique =newLinkedHashSet<>();3Set<Integer> all =newHashSet<>();45publicFirstUnique(int[] nums) {6for(intnum :...
66 map.emplace(Number("1000"), Name("A")); 67 map.emplace(Number("1001"), Name("G")); 68 map.emplace(Number("1002"), Name("E")); 69 map.emplace(Number("1003"), Name("D")); 70 71 72 unordered_map<Number, Name, MyHash, MyEqualTo>::iterator iter; 73 Number num("1001"...
Can you solve this real interview question? Unique Number of Occurrences - Given an array of integers arr, return true if the number of occurrences of each value in the array is unique or false otherwise. Example 1: Input: arr = [1,2,2,1,1,3] Outpu
firstUnique.showFirstUnique(); // return -1 基础知识没学好,不解释。已经补上了 https://leetcode.com/problems/first-unique-number/discuss/601107/JavaPython-3-DoublyLinkedList-and-LinkedHashSetdict-O(n)-2-neat-codes-w-analysis. 1. 2. ...
我们用 f[i][0] 和f[i][1] 分别表示使用字符串 binary 的第0,1,⋯,i 个字符,可以构造出的以 0/1 结尾的不同的好子序列的数目。由于「好子序列」不能包含前导 0,但本身可以为 0,那么我们可以规定「好子序列」必须以 1 开始并求出答案,如果 binary 中包含 0 就再对答案增加 1。这样做可以避免...
-1 represents obstacles that we cannot walk over. Return the number of 4-directional walks from the starting square to the ending square, that walk over every non-obstacle square exactly once. 所以不仅要递归,还要把所有能走的格子走一遍。 我们用todo变量表示剩下来要走的格点数量,当前位置和最终位...
1. Description Least Number of Unique Integers after K Removals 2. Solution Version 1 classSolution:deffindLeastNumOfUniqueInts(self,arr,k):stat={}fornuminarr:stat[num]=stat.get(num,0)+1result=sorted(stat.items(),key=lambdaitem:item[1])whilek>0:k=k-result[0][1]ifk>=0:result.pop...
链接:https://leetcode-cn.com/problems/split-a-string-into-the-max-number-of-unique-substrings/ 难度:medium 题目描述:给定一个字符串,要求切分出尽可能多的各不相同的子串。其实最多也就是一个字母一个子串,结果为s.length()。这里用了暴力解加上回溯以及相应的剪枝。