题目167(Two Sum II - Input array is sorted): 问题描述:给定一个按升序排列的整数数组 numbers 和一个目标值 target,请你找出两个数使得它们的和正好是 target。返回这两个数的下标,下标从1开始。 条件:数组已排序。 Two Sum(未排序数组) 由于数组未排序,双指针方法无法直接应用。常见解法是使用哈希表(字典...
【Description】 Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2...
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Note: Your...
LeetCode 167. Two Sum II - Input array is sorted Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, ...
167.two-sum-ii-input-array-is-sorted 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数。 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2。 说明: 返回的下标值(index1 和 index2)不是从零开始的。
Leetcode学习(2)—— Two Sum II - Input array is sorted,Givenanarrayofintegersthatisalreadysortediner.ThefunctiontwoSumshouldreturnindicesofthetwonumberssuc
原题链接在这里:https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/ 题目: Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such...
leetcode No167:https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/ Givenan array of integers thatisalready sortedinascendingorder,find two numbers such that theyaddup to a specific target number.Thefunction twoSum shouldreturnindices of the two numbers such that theyaddup to the ...
public: doublefindMedianSortedArrays(vector<int>&nums1,vector<int>&nums2) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2 nums1 = [1,3] nums2 = [2] 9 1 2 3 4 › [1,3] [2] [1,2] [3,4] Source
functwoSum1(_numbers:[Int],_target:Int)->[Int]{varmap=[Int:Int]()for(i,num)innumbers.enumerated(){ifletindex=map[target-num]{ifindex>i{return[i+1,index]}return[index,i+1]}map[num]=i+1}return[]} 【思路3】为啥老想不到双指针呢!!!