The problem "Two Sum" requires finding two numbers in aninteger arraysuch that their sum equals a specifiedtargetnumber. You need to returnthe indices ofthese two numbers, whereindices start from 0. The indices ofthe two numbers cannot be the same, and there isexactly one solutionfor each i...
我们继续写出伪代码: for i in range(len(array)): map[array[i]] = i; if target - array[i] in map: return [i, map[target - array[i]]] 这个算法看起来没什么问题,但是如果你这么写出代码来提交一定过不了。 因为有一种隐藏的情况没有考虑到,一般我们会把这种隐藏的不容易想到的情况称作“Trick...
publicint[]twoSum(int[] nums,inttarget){ Map<Integer, Integer> map =newHashMap<>();for(inti =0; i < nums.length; i++) {intcomplement = target - nums[i];if(map.containsKey(complement)) {returnnewint[] { map.get(complement), i }; } map.put(nums[i], i); }thrownewIllegalAr...
LeetCode:Two Sum 题目链接 Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your ret...
leetcode No167:https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/ Givenan array of integers thatisalready sortedinascendingorder,find two numbers such that theyaddup to a specific target number.Thefunction twoSum shouldreturnindices of the two numbers such that theyaddup to the ...
LeetCode刷题Two Sum 🍀题目 给定一个整数数组 nums 和一个整数目标值 target,请你在该数组中找出 和为目标值 target 的那 两个 整数,并返回它们的数组下标。 你可以假设每种输入只会对应一个答案。但是,数组中同一个元素在答案里不能重复出现。
leetcode算法—两数之和 Two Sum,题目Givenanarrayofintegers,returnindicesofthetwonumberssuchthattheyadduptoaspecifictarget.Youmayassumethateachin
这道题如果使用Brute Force,在LeetCode上会超时,具体程序如下: 1vector<int> twoSum(vector<int>& nums,inttarget) {2vector<int>ret;3intsz =nums.size();4for(inti =0; i < sz; i++)5for(intj = i +1; j < sz; j++)6{7if(nums[i] + nums[j] ==target)8{9ret.push_back(i);10...
复杂度分析 时间复杂度:O(n)。 空间复杂度:O(n)。 原题地址 英文版:https://leetcode.com/problems/two-sum/ 中文版:https://leetcode-cn.com/problems/two-sum/
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