1classSolution(object):2deftwoSum(self, nums, target):34forind, numinenumerate(nums):5iftarget-numinnumsandnums.index(target-num) !=ind:6return[ind, nums.index(target-num)]7return-1 直接利用了列表的索引。 运行速度仅为4ms 但是
The problem "Two Sum" requires finding two numbers in an integer array such that their sum equals a specified target number. You need to return the indices of these two numbers, where indices start from 0. The indices of the two numbers cannot be the same, and there is exactly one solut...
println(twoSum(intArrayOf(2,7,11,15),9).joinToString(",")) println(twoSum(intArrayOf(3,2,4), 6).joinToString(",")) println(twoSum(intArrayOf(3,3),6).joinToString(",")) } f="">Python: deftwoSum(nums, target): map = {} i = 0 l = len(nums) while i < l: a = num...
Two Sum 系列 1 两数之和 1.1 题目描述 1.2 解法 1.2.1 Python 1.2.2 C++ 2 两数之和2 2.1 题目描述 2.2 解法 1 两数之和 原题链接:Leetcode 1. 两数之和 1.1 题目描述 给定一个整数数组 nums 和一个目标值 target,请你在该数组中找出和为目标值的那 两个 整数,并返回他们的数组下标。 你可以...
[Lintcode two-sum]两数之和(python,双指针) 题目链接:http://www.lintcode.com/zh-cn/problem/two-sum/ 给一个整数数组,找到两个数使得他们的和等于一个给定的数target。 备份一份,然后排序。搞两个指针分别从左从右开始扫描,每次判断这两个数相加是不是符合题意,如果小了,那就把左边的指针向右移,同...
class Solution(object): def twoSum(self, nums, target): for i in range(len(nums)): if (target - nums[i]) in nums: return [i,nums.index(target - nums[i])] 1 2 3 4 5 6 然而,实际编程过程中出现了这么一个问题,Python提供的list.index(value,from,to) “左闭右开区间”,在不指定...
python3实现: 结果分析: 这种实现方法,python里面列表提供了自动检测元素存在和位置获取的方法,是有捷径可走的,别的语言用... LeetCode1:Two Sum 1. Two Sum 1.1 description Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume ...
How to append data to a parsed XML object - Python I am trying to take an xml document parsed with lxml objectify in python and add subelements to it. The problem is that I can't work out how to do this. The only real option I've found is a complete r... ...
Python Itertools Exercises, Practice and Solution: Write a Python program to find the first two elements of a given list whose sum is equal to a given value. Use the itertools module to solve the problem.
This is similar to our two sum problem where we are given two arrays and we need to find the pairs that will sum to the given sum, X. But in this case instead of two arrays, we have been given two BSTs. If we think similarly as we solved in the two sum prob...