首先,需要创建一个函数,它接受两个参数:一个整数数组和一个目标值。该函数将用于查找数组中相加和等于目标值的两个数字。 登录后复制deftwoSum(nums, target): 接下来,需要初始化两个变量登录后复制i和登录后复制j,分别设为 0。这两个变量将用于跟踪数组中相加和等于目标值的两个数字的索引。 登录后复制deftwo...
英文: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. classSolution(object):deftwoSum(self, nums, target):""":type nu...
解法一:.刚开始看到的的时候,第一个想到的就是用一个嵌套循环把nums列表遍历两次,虽然测试通过了但是耗时实在太长了,然后就考虑了其他时间复杂度低的方法 classSolution:deftwoSum(self,nums,target):""":type nums: List[int]:type target: int:rtype: List[int]"""#用len()方法取得nums列表的长度n=len(...
方法1: 蛮力 蛮力方法很简单。循环遍历每个元素 xx 并查找是否有另一个值等于目标 xtarget−x。 classSolution:deftwoSum(self, nums, target):""" :type nums: List[int] :type target: int :rtype: List[int] """foriinrange(0,len(nums)):forjinrange(i+1,len(nums)):ifnums[i] + nums[j...
如何用PYTHON找出Two Sum的结果 简介 如何用PYTHON找出Two Sum的结果 工具/原料 PYTHON 方法/步骤 1 新建一个PY文档，打开JUPTER NOTEBOOK。2 #Given nums = [2, 7, 11, 15], target = 9nums = [2, 7, 11, 15]target = 9我们要找出列表里面两个相加数为目标的数字。3 nums = [2, 7, 11, 15...
Runtime: 848 ms, faster than32.81%ofPython3online submissions forTwo Sum. 仍旧是连一半都没超过啊,娘匹西。 官方方法 Two-Pass Hash Table class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashTable = {} length = len(nums) for i in range(length): hashTabl...
classSolution:deftwoSum(self,nums,target):""":type nums:List[int]:type target:int:rtype:List[int]"""#用len()方法取得nums列表的长度 n=len(nums)#x取值从0一直到n(不包括n)forxinrange(n):#y取值从x+1一直到n(不包括n) #用x+1是减少不必要的循环,y的取值肯定是比x大foryinrange(x+1,...
Question 1 Two Sum:Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice.Example: ...
class Solution(object): def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ index_list = [] for i in range(len(nums)): for j in range(i+1, len(nums)): if nums[i] + nums[j] == target: ...
class Solution(object): def combinationSum2(self, candidates, target): """ :type candidates: List[int] :type target: int :rtype: List[List[int]] """ if not candidates: return [] candidates.sort() result = [] self.combination(candidates, target, [], result) ...