1. Two Sum Java Solutions Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would haveexactlyone solution. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 ...
【LeetCode 力扣】1. Two Sum 两数之和 Java 解法 LeetCode的第一题,英文单词书中 Abandon 一般的存在,让我们来看一下题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would haveexactlyone solution, ...
Java解法一: public class Solution { public int[] twoSum(int[] nums, int target) { HashMap<Integer, Integer> m = new HashMap<Integer, Integer>(); int[] res = new int[2]; for (int i = 0; i < nums.length; ++i) { m.put(nums[i], i); } for (int i = 0; i < nums....
public class Two_Sum_II { public int[] twoSum(int[] numbers, int target) { int[] result = new int[2]; //这里用二分搜索,我常用start和end来命名两头,middle是中间。 int start = 0; int end = numbers.length-1; //这个while循环条件很巧妙,二分搜索建议固定一个模板,这个就挺好固定的。 w...
这样sum中就储存了所有加入数字可能组成的和,每次find只要花费 O(1) 的时间在集合中判断一下是否存在就行了,显然非常适合频繁使用find的场景。 三、总结 对于TwoSum 问题,一个难点就是给的数组无序。对于一个无序的数组,我们似乎什么技巧也没有,只能暴力穷举所有可能。
push_back(dict[query]); break; } } return result; } }; // 下面是测试 int main() { Solution sol; vector<int> arr1={3,2,2,2,2,2,4}; vector<int> arr2={3,2,4}; vector<int> res1= sol.twoSum(arr1, 6); vector<int> res2= sol.twoSum(arr2, 6); for(int i:res1) ...
1// 对撞指针2// 时间复杂度: O(n)3// 空间复杂度: O(1)4class Solution{5public:6vector<int>twoSum(vector<int>&numbers,int target){7int l=0,r=numbers.size()-1;8while(l<r){9if(numbers[l]+numbers[r]==target){10int res[2]={l+1,r+1};11returnvector<int>(res,res+2);12}...
这里我只写了2Sum和3Sum的代码,注意要避免重复排序,同时避免重复数字的循环。 代码如下: AI检测代码解析 import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Solution { //javascript:void(0) //K sum 可以递归去做 ...
函数部分 ` public class Solution { public int[] twoSum(int[] nums, int target) { int [] answer = new int[2]; int answer_one = 0; int answer_two = 0; int end = 0; for(int i = 0 ;i<nums.length; i++) { answer_one = i; ...
Solution public class Solution { public int twoSum2(int[] nums, int target) { if (nums == null || nums.length == 0) return 0; Arrays.sort(nums); int count = 0; int left = 0, right = nums.length-1; while (left < right) { ...