1. Two Sum Java Solutions Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would haveexactlyone solution. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 ...
【LeetCode 力扣】1. Two Sum 两数之和 Java 解法 LeetCode的第一题,英文单词书中 Abandon 一般的存在,让我们来看一下题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would haveexactlyone solution, ...
public class Two_Sum_II { public int[] twoSum(int[] numbers, int target) { int[] result = new int[2]; //这里用二分搜索,我常用start和end来命名两头,middle是中间。 int start = 0; int end = numbers.length-1; //这个while循环条件很巧妙,二分搜索建议固定一个模板,这个就挺好固定的。 w...
最后,如果 TwoSumI中给的数组是有序的,应该如何编写算法呢?答案很简单,前文 双指针技巧汇总 写过:int[]twoSum(int[]nums,int target){int left=0,right=nums.length-1;while(left<right){int sum=nums[left]+nums[right];if(sum==target){returnnewint[]{left,right};}elseif(sum<target){left++;/...
这里我只写了2Sum和3Sum的代码,注意要避免重复排序,同时避免重复数字的循环。 代码如下: import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Solution { //javascript:void(0) //K sum 可以递归去做 /*
更多文章查看个人博客 个人博客地址:twoSum 两数之和 【JAVA实现】 方法一 使用双重循环两两相加判断是否等于目标值 public List<String> twoSum2(int[] arr, int sum) { if (arr == null || arr.length == 0) { return new ArrayList<>(); } List<String> list = new ArrayList<>(); for (int...
push_back(dict[query]); break; } } return result; } }; // 下面是测试 int main() { Solution sol; vector<int> arr1={3,2,2,2,2,2,4}; vector<int> arr2={3,2,4}; vector<int> res1= sol.twoSum(arr1, 6); vector<int> res2= sol.twoSum(arr2, 6); for(int i:res1) ...
1// 对撞指针2// 时间复杂度: O(n)3// 空间复杂度: O(1)4class Solution{5public:6vector<int>twoSum(vector<int>&numbers,int target){7int l=0,r=numbers.size()-1;8while(l<r){9if(numbers[l]+numbers[r]==target){10int res[2]={l+1,r+1};11returnvector<int>(res,res+2);12}...
Solve two sum problem (Javascript, Java, C#, Swift, Kotlin, Python, C++, Golang) Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same el...
函数部分 ` public class Solution { public int[] twoSum(int[] nums, int target) { int [] answer = new int[2]; int answer_one = 0; int answer_two = 0; int end = 0; for(int i = 0 ;i<nums.length; i++) { answer_one = i; ...