使用双重循环两两相加判断是否等于目标值 publicList<String>twoSum2(int[] arr,intsum){if(arr ==null|| arr.length ==0) {returnnewArrayList<>(); } List<String> list =newArrayList<>();for(inti=0; i < arr.length -1; i++) {for(intj=i +1; j < arr.length -1; j++) {if(arr[i...
classSolution {publicint[] twoSum(int[] nums,inttarget) { Hashtable<Integer,Integer> map =newHashtable<Integer,Integer>();for(inti = 0; i < nums.length; i++) { map.put(nums[i],i); }for(inti = 0; i < nums.length; i++) {intanother = target -nums[i];//过滤元素本身if( ...
import java.util.HashMap; public class Solution { public int[] twoSum(int[] nums, int target) { HashMap<Integer, Integer> hashMap = new HashMap<Integer, Integer>(); int[] res = new int[2]; for (int i = 0; i < nums.length; i++) { if (hashMap.get(target - nums[i]) =...
import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Solution { //javascript:void(0) //K sum 可以递归去做 /* * 2Sum问题的求解:排序外加双指针来实现 * */ public List<List<Integer>> twoSum(int[] nums,int target) { List<List<Integer>> twoResList=...
1. Two Sum 文字思想: 遍历数组中所有元素,假设当前遍历到到的数是A,下标是i,我们构建HashMap为(期待的加数 = target - A, A),则A+期待的加数=target。对每一个遍历到的数,我们看看它是否存在与HashMap的key…
每天一算:Two Sum leetcode上第1号问题:Two Sum 给定一个整数数组和一个目标值,找出数组中和为目标值的两个数。 你可以假设每个输入只对应一种答案,且同样的元素不能被重复利用。 示例: 给定 nums = [2, 7, 11, 15], target = 9 因为 nums[0] + nums[1] = 2 + 7 = 9 所以返回 [0, 1]...
Java:使用计算器sumTwoNumbers、subtractTwoNumbers、divideTwoNumbers和multiplyTwoNumbers测试失败任务描述:在...
第一道题Two Sum如下: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned...
java版本的实现: publicint[]twoSum(int[]numbers,inttarget){inti=0;intj=numbers.length-1;int[]res=newint[2];while(i<j){intcur=numbers[i]+numbers[j];if(cur==target){res[0]=i+1;res[1]=j+1;returnres;}elseif(cur>target)j--;elsei++;}returnres;} ...
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