【Description】 Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2...
Input:numbers = [2,7,11,15], target = 9 Output:[1,2] Explanation:The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 = 2. We return [1, 2]. Example 2: Input:numbers = [2,3,4], target = 6 Output:[1,3] Explanation:The sum of 2 and 4 is 6. Therefore index1 ...
1.1 英文描述 Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2...
Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note ...
LeetCode 0167. Two Sum II - Input array is sorted两数之和 II - 输入有序数组【Easy】【Python】【双指针】 题目 英文题目链接 Given an array of integers that is already sorted_牛客网_牛客在手,offer不愁
167.Two Sum II - Input array is sorted(双指针法) Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target...
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. ...
167. Two Sum II - Input array is sorted Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where in...
functwoSum1(_numbers:[Int],_target:Int)->[Int]{varfront=0vartail=numbers.count-1whilefront<tail{ifnumbers[front]+numbers[tail]==target{return[front+1,tail+1]}ifnumbers[front]+numbers[tail]<target{front+=1}else{tail-=1}}return[]}...
public int[] twoSum(int[] numbers, int target) { int[] num=new int[2]; for(int i=0;i<numbers.length;i++){ //从下一个元素之后查找target-numbers[i] int index=BinarySerch(numbers,i+1,target-numbers[i]); if(index!=-1){ ...