publicint[] TwoSum(int[] nums,inttarget) {for(intindex =0; index < nums.Length; index++){intelement =nums[index];intotherElement = target - element;//查找是否存在intotherIndex = nums.ToList().IndexOf(otherElement);//主要是这一步if(otherIndex != -1&& otherIndex !=index){returnnew...
Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note ...
index); break; } if (sort_array[j].value + sort_array[i].value > target ){ j--; } else if(sort_array[j].value + sort_array[i].value < target ){ i++; } } return idx; } }; 方案二: 哈希表 class Solution { public: unordered_map<int,int> mp1; vector<int> twoSum(vec...
for i in range(len(array)): for j in range(len(array)): if array[i] + array[j] == target: return [i, j] 这样做当然是正确的,但显然不是最好的答案。根据经验,一般情况下O(n2)的算法都不是最优解。 引入map 如果你熟悉C++ STL或者其他语言工具库的用法,想必应该很容易想到可以使用map。
Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. ...
167.two-sum-ii-input-array-is-sorted 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数。 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2。 说明: 返回的下标值(index1 和_牛客网_牛客在手,offer不愁
Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. ...
Greatest Sum Divisible by Three sdncomdpversion博客 文章作者:Tyan 博客:noahsnail.com | CSDN | 简书 Tyan 2021/08/06 3510 Leetcode 321. Create Maximum Number sdncomversion博客 文章作者:Tyan 博客:noahsnail.com | CSDN | 简书 Tyan 2021/02/04 3000 Leetcode 1752. Check if Array Is Sorted ...
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