leetcode 【 Two Sum 】python 实现 题目: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please not...
"""hashDict = {}foriinrange(len(nums)): x = nums[i]iftarget-xinhashDict:return(hashDict[target-x], i) hashDict[x] = i 此方法,在速度排行打败57%的方案 参考 https://stackoverflow.com/questions/30021060/two-sum-on-leetcode
Runtime: 848 ms, faster than32.81%ofPython3online submissions forTwo Sum. 仍旧是连一半都没超过啊,娘匹西。 官方方法 Two-Pass Hash Table class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashTable = {} length = len(nums) for i in range(length): hashTabl...
PYTHON 方法/步骤 1 新建一个PY文档，打开JUPTER NOTEBOOK。2 #Given nums = [2, 7, 11, 15], target = 9nums = [2, 7, 11, 15]target = 9我们要找出列表里面两个相加数为目标的数字。3 nums = [2, 7, 11, 15]target = 9nums2 = numsfor a, j in enumerate(nums): for b, k in ...
classSolution:deftwoSum(self,nums:List[int],target:int)->List[int]:foriinrange(0,len(nums)):remain=target-nums[i]#print(remain)ifremaininnumsandnums.index(remain)!=i:returni,nums.index(remain) 结果: 3. Hash Table In Python, the hash table we use is the dictionary. ...
def twoSum(nums, target):hashmap = {}for i, num in enumerate(nums):diff = target - numif diff in hashmap:return [hashmap[diff], i]hashmap[num] = i``` 相关知识点: 试题来源: 解析[0, 1]这段代码是典型的两数之和解法,使用哈希表优化时间复杂度。以下完整解析:...
public class TwoSum { public static void main(String[] args) { int arr[] = {3,2,5,7,11}; int[] resultArr = new int[2]; HashMap map = new HashMap(); for(int i=0; i<arr.length; i++){ int result = 9 - arr[i]; ...
Given an array of integers that is alreadysorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note...
参考代码(Python): def twoSum(nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ hashmap = {} for i in range(len(nums)): complement = target - nums[i] if complement in hashmap: return [hashmap[complement], i] hashmap[nums[i]] = i return...
def twoSum(self, nums: List[int], target: int) -> List[int]: hashtable = dict() for i, num in enumerate(nums): if target - num in hashtable: return [hashtable[target - num], i] hashtable[nums[i]] = i return [] 官方给出的答案里,有些函数和语句可能不太了解,这里我说明一下...