binaryTree.inOrderTraversal(); System.out.println(""); binaryTree.postOrderTraversal(); }publicstaticclassBinaryTree {privateNode root;publicvoidpreOrderTraversal() {this.root.preOrderTraversal(); }publicvoidinOrderTraversal() {this.root.inOrderTraversal(); }publicvoidpostOrderTraversal() {this.ro...
* @param root: A Tree * @return: Inorder in ArrayList which contains node values. */vector<int>inorderTraversal(TreeNode * root){// write your code herevector<int> result; traverse(root, result);returnresult; }// 遍历法的递归函数,没有返回值,函数参数result贯穿整个递归过程用来记录遍历的结...
If we classify binary tree traversals, inorder traversal is one of traversal which is based on depth-first search traversal. The basic concept for inorder traversal lies behind its name. "In" means between and that's why the root is traversed in between its left & right subtree...
* TreeNode(int x) { val = x; } * } */classSolution{public List<Integer>inorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){// left firstif(current.left==null){result.add(current.val);current=current.right...
题目描述(中等难度) 二叉树的中序遍历。 解法一 递归 学二叉树的时候,必学的算法。用递归写简洁明了,就不多说了。 publicList<Integer>inorderTraversal(TreeNoderoot){List<Integer>ans=newArrayList<>();getAns(root,ans);returnans;}privatevoidgetAns(TreeNodenode,List<Integer>ans){if(node==null){retur...
对于DFS,Binary Tree 有三种traversal的方式: ** Inorder Traversal: left -> root -> right ** Preoder Traversal: root -> left -> right ** Postoder Traveral: left -> right -> root 记忆方式:order的名字指的是root在什么位置。left,right的相对位置是固定的。
Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: [] Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is...
=root){val queue=LinkedList<TreeNode>()queue.offer(root)while(queue.isNotEmpty()){val levelList=mutableListOf<Int>()val size=queue.size// 此处的for循环会把当前 level 层的所有元素poll出来,同时把下一层待遍历的节点放入队列for(iin0..size-1){// removes the head (first element) of this ...
LeetCode之“树”:Binary Tree Preorder && Inorder && Postorder Traversal,BinaryTreePreorderTraversal题目链接题目要求:Givenabinarytree,returnthepreordertraversalofitsnodes'values.Forexample:Givenbinarytree{1...
18 A and B are two nodes on a binary tree. In the in-order traversal, the condition for A before B is ( ). A. A is to the left of B B. A is to the right of B C. A is the ancestor of B D. A is a descendant of B ...