classSolution{public:voidswap(int& a,int& b){ a ^= b; b ^= a; a ^= b; }intthirdMax(vector<int>& nums){intsz = nums.size();if(sz ==1){returnnums[0]; }elseif(sz ==2){returnmax(nums[0], nums[1]); }inta = nums[0];intb =0;intc =0;boolsecond =false;// the s...
Leetcode 数组:414 第三大的数 third-maximum-number 给定一个非空数组,返回此数组中第三大的数。如果不存在,则返回数组中最大的数。要求算法时间复杂度必须是O(n)。 classSolution:defthirdMax(self, nums: List[int]) ->int: nums=list(set(nums)) MAX= float('-inf') SECEND_MAX= float('-inf')...
Explanation: Note that the third maximum here means the third maximum distinct number. Both numbers with value 2 are both considered as second maximum. Solution 1 用两个标识符表示,第二大的数和第三大的数是否已经赋值。 classSolution{public:intthirdMax(vector<int>& nums){if(nums.size() ==1)...
【leetcode】414. Third Maximum Number problem 414. Third Maximum Number solution 思路:用三个变量first, second, third来分别保存第一大、第二大和第三大的数,然后遍历数组。 classSolution {public:intthirdMax(vector<int>&nums) {//1.LONG_MIN;longfirst = LONG_MIN, second = LONG_MIN, third = L...
Both numbers with value 2 are both considered as second maximum. 思路分析 给一个非空的整数数组,返回第三大的数字,不足三个返回最大的数字; 时间复杂度必须为O(n) 比较简单,只要维持一个大小3的优先队列不断更新即可 源码附录 classSolution{publicintthirdMax(int[] nums){if(nums==null|| nums.length...
classSolution {public:intthirdMax(vector<int>&nums) { sort(nums.begin(), nums.end()); auto it=unique(nums.begin(), nums.end()); nums.erase(it, nums.end());intn =nums.size();if(n >2)returnnums[n -3];elsereturnnums[n -1]; ...
max1 : max3;31}32} 参考资料: https://discuss.leetcode.com/topic/63715/java-neat-and-easy-understand-solution-o-n-time-o-1-space LeetCode 题目列表 -LeetCode Questions List
Explanation: Note that the third maximum here means the third maximum distinct number. Both numbers with value 2 are both considered as second maximum. classSolution{public:intthirdMax(vector<int>& nums){ set<int> s;for(intnum : nums) { ...
LeetCode "Third Maximum Number" 6 Straight-forward strategy.. please take care of all details - data type, assignment order etc. classSolution {public:intthirdMax(vector<int>&nums) {longlongv1, v2, v3; v1= v2 = v3 = std::numeric_limits<longlong>::min();...
Leetcode-414 Third Maximum Number(第三大的数) 1classSolution2{3public:4constlonglongintMikuMikuMi = -393939393939;5intthirdMax(vector<int>&nums)6{7longlongintmax1 = MikuMikuMi,max2 = MikuMikuMi,max3 =MikuMikuMi;8for(auto d:nums)9{10if(d>max1)11{12max3 =max2;13max2 =max1;14max...