(ii) Find the equation of the tangent to the curve y=x^2√ (3+x) at the point where x=1.(iii) Find the coordinates of the turning points of the curve y=x^2√ (3+x). 相关知识点: 试题来源: 解析 (i) x=1correctly substitute their\ 12(3+x)^(- 1/2)and their\ 2...
The equation of a curve is 5x^2-2xy+3y^2-70=0.Find the co-ordinates of the point on the curve where the tangent is parallel to the y axis. 相关知识点: 试题来源: 解析 (√ (15), (√ (15))3) or (-√ (15),- (√ (15))3) ...
The equation of a curve is xy=12 and the equation of a line l is 2x+y=k, where k is a constant.In the case where k=11, find the co-ordinates of the points of intersection of l and the curve.相关知识点: 试题来源: 解析 Points of intersection are (1.5,8) and (4,3) ...
百度试题 结果1 题目The equation of a curve is given by y=xe^(-2x).Using your answer to part (i), find y=xe^(-2x).(i) e^(-2x)(1-2x) 相关知识点: 试题来源: 解析 (-xe^(-2x))2- (e^(-2x))4+c
of概念坐标平面假设在xy-平面上给定了一条曲线(图1),方程φ(z,y)=0称为一条曲线的隐式方程,如果这条曲线上的任一点的坐标(z,y)满足它,并且满足这个方程妒(z,y)=0的任意一对数z,Y是这条曲线上一个点的坐标.显然,一条曲线由它的方程所确定,因而,我们可以说用它的方程表示的曲线.VIP中学数学教学参考...
1 A-LEVEL的数学题The equation of a curve is y =6/(5 - 2x)(i) Calculate the gradient of the curve at the point where x=1.(ii) A point with coordinates (x,y) moves along the curve in such a way that the rate of increase ofy has a constant value of 0.02 units per second....
Define Equation of a curve. Equation of a curve synonyms, Equation of a curve pronunciation, Equation of a curve translation, English dictionary definition of Equation of a curve. an equation which expresses the relation between the coördinates of eve
have a 2D plot and it seems quadratic. I got it from a data set which is obtained numerically from a calculation. i know the equation can be obtained by fitting the data sets. It seems Python automatically fitted from the data points. I need to print the equation of the fitted curve....
two points. Therefore, for finding out the equation for a curve between two points, we need to substitute the coordinates of the two points into the general equation of the curve. For instance, let us take the curve to be a straight line. We know that the general ...
y=(1/x)+k y'=-1/x^2 y=(1/3)x^3 y'=x^2 ∵-1/x^2*x^2=-1 ∴两条曲线的切线互相垂直