find the equation of the normal to the curve y=3x2-2x-1which is perpendicular to the line y=x-3Solution:y = 3x^2 - 2x - 1 (1) Its derivative is dy/dx = 6x - 2Let the equation of tangent line be y = mx + c1 = x + c1 (2)(Tangent line is parallel to y = x - 3,...
百度试题 结果1 题目【题目】Find the equation of the normal to the curve a the point with the given x-coordinate.y=1-x^2wherex=0 相关知识点: 试题来源: 解析 【解析】x=0 反馈 收藏
find the equation of the normal to the curve at te point with the given x-coordinate y=1-x2(x的2次方) where x=0 这道题我切线求斜率求得是0 如果对 那法线斜率多少 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 答案是对的法线斜率不存在,倾角90度 解析看不懂?免费...
题目1.Find the equation of the tangent to the curve y=x2,which is parallel to the x-axis2.Find the equation of the tangent to the curve y=x2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x2-2x-1 whi...
本人在国外读a levelfind the equation of the tangent to the curve y=x2-2x which is prependicular to the line y=x-3说错了 是这一题 find the equation of the normal to the curve at te point with the given x-coordinate y=1-x2 where x=0
百度试题 结果1 题目11. Find the equation of the normal to the curve y = 3 + 2x-x2 which is parallel to the line 2y - x = 3. 相关知识点: 试题来源: 解析 2y-x=4 反馈 收藏
结果1 题目6)Find the equation of the normal to the curve y=(3x)/(2x-3)atlneoig in2x-3 相关知识点: 试题来源: 解析 at the origin so gradient normal is 1 and the origin is (0,0) So the equation of the normal is 反馈 收藏 ...
Find the equation of the normal to the curve y=2x2+3sinx at x=0. View Solution The equation of normal to the curve y2=8x is View Solution Knowledge Check The equation of the normal to the curve y=x+sinxcosx at x=π2, is Ax=2 Bx=π Cx+π=0 D2x=πSubmit The equation of...
Find the equations of the normal to the curvey=x3+2x+6which are parallel to the linex+14y+4=0. View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
Answer to: Find the equation of the line normal to the curve y = 8 - x^3 at the point (-1, 9). By signing up, you'll get thousands of step-by-step...