find the equation of the normal to the curve y=3x2-2x-1which is perpendicular to the line y=x-3Solution:y = 3x^2 - 2x - 1 (1) Its derivative is dy/dx = 6x - 2Let the equation of tangent line be y = mx + c1 = x + c1 (2)(Tangent line is parallel to y = x - 3,...
【题目】Find the equation of the normaltothe curve y= 1- x2at the point(1. 0) and show this normal onyour graph. 相关知识点: 试题来源: 解析 【解析】tangent3Draw the cure y = 1-x2using the same scale onboth axes.2y-x+1=0 ...
find the equation of the normal to the curve y=3x2-2x-1which is perpendicular to the line y=x-3 Solution:y = 3x^2 - 2x - 1 (1) Its derivative is dy/dx = 6x - 2 Let the equation of tangent line be y = mx + c1 = x + c1 (2)(Tangent line is parallel to y = x - ...
【题目】Find the equation of the normal to the curve x = cos 0,y = sin θ at the point where θ = n. Find the coordinates ofthe point where this normal cuts the curve again. 相关知识点: 试题来源: 解析 |y=x;(-1/2√2,-1/2√2) 结果一 题目 Find the equation of the normal ...
百度试题 结果1 题目【题目】Find the equation of the normal to the curvewith parametric equations x=e^t , y=e^t+e^(-t) , at the point p, where t=o 相关知识点: 试题来源: 解析 【解析】=1 反馈 收藏
百度试题 结果1 题目【题目】Find the equation of the normal to the curve a the point with the given x-coordinate.y=1-x^2wherex=0 相关知识点: 试题来源: 解析 【解析】x=0 反馈 收藏
,which is parallel to the x-axis 2.Find the equation of the tangent to the curve y=x2-2x which is perpendicular to the line 2y=x-1 3.Find the equation of the normal to the curve y=3x2-2x-1 which is parallel to the line y=x-3 ...
Find the equation of the normal tothe curvey = 1- x2atthepoint(1, 0, and show this normal onyour graph.10)normal22tangent3(2,-3)Draw the curve y = 1 - x2using the same scale onboth axes. 相关知识点: 试题来源: 解析 2y-x+1=0 ...
百度试题 结果1 题目 A curve has equation y=√ x, x≥ 0. Find the equation of the normal to the curve at the point A, where x=1. 相关知识点: 试题来源: 解析 y+2x-3=0 反馈 收藏
结果一 题目 Find the equation of the normal to the curve y = 4 × 5* at the point (1, 20). 答案 ζ'[3cη](x+1+r-=4(ζ'3cosζ)相关推荐 1Find the equation of the normal to the curve y = 4 × 5* at the point (1, 20)....