结果1 题目【题目】已知$$ \tan \theta = 2 $$1则$$ \frac { \sin ( \frac { \pi } { 2 } + \theta ) - \cos ( \pi - \theta ) } { \sin ( \frac { \pi } { 2 } + \theta ) - \sin ( \pi - \theta ) } $$等于() A.2 B.-2 C.0 D.$$ \frac { 2...
1+tan^(2)theta) का मान होगा : 01:59 बिन्दु (3,0) का X-निर्देशांक होगा : 01:55 यदि गोले का व्यास 14 से. मी. है, तो उसकी...
Let fn(Theta)=(tan(Theta/2))(1 +sec(Theta))(1+sec(2Theta))...(1+sec(2^nTheta).. then
On the other hand, we also need to simplify the equation. Answer and Explanation: We are given the equation {eq}(\tan(\theta )+ 1) (\sec(\theta) - 2) = 0 {/eq}. Solving for {eq}\theta {/eq} in the interval {eq}0 \leq \theta <......
【解析】 (1)由$$ \tan \theta = - \frac { 1 } { 2 } $$得: $$原式 式 = \frac { \sin ^ { 2 } \theta - 2 \sin \theta \cdot \cos \theta - \cos ^ { 2 } \theta } { 4 \cos ^ { 2 } \theta - 3 \sin ^ { 2 } \theta + \sin ^ { 2 } \theta + ...
Answer to: Verify that the equation is an identity. Show that (sec theta + tan theta)^2 = (1 + sin theta)/(1 - sin theta). By signing up, you'll...
结果1 题目【题目】若$$ \tan \theta = 1 $$,则sin2θ的值为( ) A.$$ \frac { \sqrt { 2 } } { 2 } $$ B. 1 C.$$ \frac { 1 } { 2 } $$ D.$$ \frac { \sqrt { 3 } } { 2 } $$ 相关知识点: 试题来源: 解析 【解析】∵$$ \tan \theta = 1 , $$ , ...
θ=tan−1(2tan2θ)−tan−1((1/3)tanθ), if tanθ is equal to A−2 B−1 C2/3 D2Submit Prove that: cos2θ(1+tan2θ)=1. View Solution Show that : 1+tan θ21−tan θ2=1+sinθcosθ=tan(π4+θ2) View Solution prove that 1+tanθtan2θ=sec2θ View Solution...
If int(0)^(1) f(t)dt=x^2+int(0)^(1) t^2f(t)dt, then f'(1/2)is 02:57 The value of the integral int(-2)^2 sin^2x/(-2[x/pi]+1/2)dx (where [x]... 06:18 The integral int(pi//6)^(pi//4)(dx)/(sin2x(tan^(5)x+cot^(5)x)) equals 07:33 Let f and g...
【解析】 解:$$ \tan ( \theta + \varphi ) = \frac { \tan \theta + \tan \varphi } { 1 - \tan \theta \tan \varphi } = \frac { \frac { 1 } { 2 } + \frac { 1 } { 3 } } { 1 - \frac { 1 } { 2 } \times \frac { 1 } { 2 } } = 1 . $$ ∵法...