jsonData, encoding: .utf8) } let dictionary: [String: Any] = ["name": "John Doe", "age": 30, "isDeveloper": true] if let jsonString = dictToJsonString(dict: dictionary) { print("JSON String: \(jsonString)") } else { print("Failed to convert dictionary to JSON string") } ...
JSONSerialization.data(withJSONObject: self, options: [])else{returnnil } guard letstring= String(data: data, encoding: .utf8)else{returnnil }returnstring} } extension String {publicfunc toDictionary() ->[String : Any] {varresult =[String : Any]() guard!self.isEmptyelse{returnresult } ...
value)都关联独特的键(key),键作为字典中的这个值数据的标识符。和数组中的数据项不同,字典中的数据项并没有具体顺序。我们在需要通过标识符(键)访问数据的时候使用字典 */ //(1)创建一个字典 var dic:Dictionary<String,String>=["三国演义":"罗贯中","水浒传":"施耐庵","红楼梦":"曹雪芹","西游记":"...
importFoundationfuncdictionaryToJsonString(data:[String:Any])->String?{do{letjsonData=tryJSONSerialization.data(withJSONObject:data,options:[])letjsonString=String(data:jsonData,encoding:.utf8)returnjsonString}catch{print("Error converting dictionary to JSON:\(error)")returnnil}}letuserJsonString=di...
1//JSON字符串2let str:String ="{\"server\":\"192.168.0.1\",\"port\":\"88\",\"username\":\"administrator\",\"password\":\"123456\"}"3print(str)4//Print {"server":"192.168.0.1","port":"88","username":"administrator","password":"123456"}56//JSON字符串转换为字典(Dictionary)...
// here "jsonData" is the dictionary encoded in JSON data } catch let error as NSError { print(error) } do { let decoded = try NSJSONSerialization.JSONObjectWithData(jsonData, options: []) as? [String:String] // here "decoded" is the dictionary decoded from JSON data } catch let...
NSString *strs=[[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]; return strs; } 利用NSJSONSerialization序列化成NSData,再通过NSString 转成JSON字符串 func toJSONString(dict:NSDictionary!)->NSString{ var data = NSJSONSerialization.dataWithJSONObject(dict...
Swift中字典与JSON转换的⽅法 Swift中经常会遇到字典和字符串的相互转换，因此可以转换可以封装起来，转换代码如下:func convertStringToDictionary(text: String) -> [String:AnyObject]? { if let data = text.data(using: String.Encoding.utf8) { do { return try JSONSerialization.jsonObject(with: data,...
let simplifiedModel: [String: [String: Double]] = decodedModel.flatMap { [$0.name: $0.model] } 但我得到了一个错误: 无法将“[Dictionary<String,[String:Double]>.Element]”类型的值转换为闭包结果类型“[String:[String:Double]]” 我该怎么做呢?
使用JSONSerialization的isValidJSONObject(_:)方法检查字典是否可以转换为 JSON。 调用data(withJSONObject:options:)方法进行转换。 下面是代码示例: importFoundationfuncconvertDictionaryToJSON(dictionary:[String:Any])->String?{// 检查字典是否有效guardJSONSerialization.isValidJSONObject(dictionary)else{print("无效...