{ guard let data=try? JSONSerialization.data(withJSONObject: self, options: [])else{returnnil } guard letstring= String(data: data, encoding: .utf8)else{returnnil }returnstring} } extension String {publicfunc to
struct Category:JSONable{varid:Stringvarcount:Intvarcovers:[String]convenienceinit(data:JSON){id=data["id"].stringValue count=data["count"].intValue covers=data["covers"].arrayValueas![String]}staticfuncfromJSON(data:JSON){returnself.init(id:data["id"].stringValue,count:data["count"].intV...
[String:Any]{print("JSON to Dictionary:\(jsonObject)")ifletname=jsonObject["name"]as?String{print("Name:\(name)")}ifletage=jsonObject["age"]as?Int{print("Age:\(age)")}ifletcity=jsonObject["city"]as?String{print("City:\(city)")}}}catch{print("Error deserializing JSON:\(error....
importFoundationfuncdictionaryToJsonString(data:[String:Any])->String?{do{letjsonData=tryJSONSerialization.data(withJSONObject:data,options:[])letjsonString=String(data:jsonData,encoding:.utf8)returnjsonString}catch{print("Error converting dictionary to JSON:\(error)")returnnil}}letuserJsonString=di...
let jsonObject: [String: Any] = [ "userId": "1234", "nickname": "lilei", ] let model = Model.deserialize(from: object) 但是存在兼容和安全方面的问题,由于强依赖内存布局规则,Swift 大版本升级时可能会有稳定性问题。同时由于要在运行时通过反射解析数据结构,会对性能有一定影响 ...
在Swift中,将JSON转换为数据类型通常涉及到使用`Codable`协议,这是Swift 4引入的一个特性,用于简化JSON的编码和解码过程。`Codable`协议结合了`Encodable`和`...
这里笔者通过反射机制来实现json转模型(由于项目中使用到了SwiftyJSON,因此添加了JOSN转化为模型方法)。模型基类代码如下 importUIKitimportSwiftyJSONclassBQModel:NSObject{requiredoverrideinit() { }requiredinit(_dic:Dictionary<String,Any>) {super.init()self.configValue(dic) ...
Add functionality to existing types using extensions, and cut down on boilerplate code with custom string interpolations. extension Player: Codable, Equatable {} import Foundation let encoder = JSONEncoder() try encoder.encode(player) print(player) // Prints "Player(name: "Tomas", highScore: 50...
JSONSerialization.jsonObject(with: data, options: []) guard let jsonDictonary = jsonResponse as? [String: Any] else { onFailure("Error parsing JSON response.") return } guard let responseToken = jsonDictonary["access_token"] as? String else { onFailure("Error retrieving token fro...
var object: Dictionary<String, JSONValue>? 注意每一种属性都是一个Optional值。这是因为JSON数据能包含任何它定义的有效类型。 因此，建议的方式是用Optional绑定检索值： if let name = userName.string{ //This could avoid lots of crashes caused by the unexpected data types } if...