leetcode 24. Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only c
LeetCode-Swap Nodes in Pairs Description: Given a linked list, swap every two adjacent nodes and return its head. You may not modify the values in the list’s nodes, only nodes itself may be changed. Example: AI检测代码解析 Given 1->2->3->4, you should return the list as 2->1->...
node3.next= &node4; ListNode* ii =swapPairs(list1);while(ii !=NULL) { cout<< ii->val <<endl; ii= ii->next; } system("pause");return0; } 下面是不使用指向指针的指针,而是新建一个头节点的解决方式(同样,在代码中判断下两个节点是否都存在,使用while条件的语句简化): ListNode* swapPairs...
24. Swap Nodes in Pairs Medium Topics Companies Given a linked list, swap every two adjacent nodes and return its head. You must solve the problem without modifying the values in the list's nodes (i.e., only nodes themselves may be changed.) Example 1: Input: head = [1,2,3,4] ...
leetcode:Swap Nodes in Pairs Given a linked list, swap every two adjacent(相邻的) nodes and return its head. For example, Given1->2->3->4, you should return the list as2->1->4->3. Your algorithm should use only constant space. You maynotmodify the values in the list, only ...
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed. Thinking 递归思考 局部交换(): 对于一个node,首先对它进行判断: 是none? 下一个元素是none?(即只有这一个元素)那么什么都不干,返回。反之,和node.next交换,node.next = 局...
Leetcode-Swap Nodes in Pairs 一、题目——Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example, Given1->2->3->4, you should return the list as2->1->4->3. Your algorithm should use only constant space. You maynotmodify the values...
*//** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */publicclassSolution{/** * @param head a ListNode * @return a ListNode */publicListNodeswapPairs(ListNodehead){ListNodedummy=newListNode(0);dummy...
Given a linked list, swap every two adjacent nodes and return its head. 全栈程序员站长 2022/07/06 1720 24. 两两交换链表中的节点 编程算法 来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/swap-nodes-in-pairs 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 lucife...
Swap Nodes in Pairs For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Solution public class Solution { public ListNode swapPairs(ListNode head) { if (head == null || head.next == null) return head; ...