24: Swap Nodes in Pairs https://oj.leetcode.com/problems/swap-nodes-in-pairs/ Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You ...
classSolution {public: ListNode* swapPairs(ListNode*head) {//对象在栈上分配内存,不需要手动释放内存//指针在堆上分配内存,需要手动释放内存,避免内存泄漏ListNode dummy(0,head);//初始化列表的形式创建对象,作为哨兵节点auto node0=&dummy; auto node1=head;//至少有两个节点while(node1 && node1->next)...
unwrap().next } } 题目链接: Swap Nodes in Pairs : leetcode.com/problems/s 两两交换链表中的节点: leetcode-cn.com/problem LeetCode 日更第 33 天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励支持小满 点击下方卡片关注小满,领红包封面,加个人微信 让我们深度链接, 年一起讨论,共同进步～...
24. Swap Nodes in Pairs Medium Topics Companies Given a linked list, swap every two adjacent nodes and return its head. You must solve the problem without modifying the values in the list's nodes (i.e., only nodes themselves may be changed.) Example 1: Input: head = [1,2,3,4] ...
给你一个链表,两两交换其中相邻的节点,并返回交换后链表的头节点。你必须在不修改节点内部的值的情况下完成本题(即,只能进行节点交换)。 示例1: 输入:head = [1,2,3,4]输出:[2,1,4,3] 示例2: 输入:head = []输出:[] 示例3: 输入:head = [1]输出:[1] ...
Can you solve this real interview question? Swap Nodes in Pairs - Given a linked list, swap every two adjacent nodes and return its head. You must solve the problem without modifying the values in the list's nodes (i.e., only nodes themselves may be chan
leetcode 24. Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, only ...
我的思路是迭代。依然是给一个dummy节点放在head节点之前,然后dummy.next是head节点,nextStart是第三个节点,需要交换的只是l2和l2.next,l1永远是需要swap的两个节点之前的那个节点,他不参与swap。每次交换完了之后只往前挪动一个节点的距离。我画了一个示意图,这样不容易错。
LeetCode 24 Swap Nodes in Pairs(交换序列中的结点) 翻译 给定一个链表,调换每两个相邻节点,并返回其头部。 例如, 给定1->2->3->4, 你应该返回的链表是2->1->4->3。 你的算法必须使用唯一不变的空间。 你也不能修改列表中的值,只有节点本身是可以改变的。
[LeetCode] Swap Nodes in Pairs 成对交换节点 Given a linked list, swap every two adjacent nodes and return its head. For example, Given1->2->3->4, you should return the list as2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list,...