求首个个位上是的正整数之和. Find the sum of the first positive integers with unit digit . 相关知识点: 试题来源: 解析 . 首个个位数字是的正整数分别为: ,,, 这个数字之和为: , 故首个个位数字是的正整数之和为.反馈 收藏
1. for any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2. what is the sum of all the even integers between 99 and 301?A 10,100B 20,200C 22,650D 40,200E 45,150 相关知识点: 试题来源: 解析 选择B解释:对任意整数n 前n项和是[n(n+1)]/2...
The sum of the first k positive integers is equal to frack(k+1)2frack(k+1)2 . What is the sum of the integers from n to m, inclusive, where 0<n<m0<n<m ? 选项: A、 m(m+1)2−(n+1)(n+2)2m(m+1)2−(n+1)(n+2)2...
For any positive integer n , the sume of the first n positive integers equal [n/(n+1)]/2.What is the sum of all the even integers between 99and 301? A10100 B 20200 C 22650 D 40200 E 45150 解答: 点赞0 阅读3547 解答: sysadmin老师 ...
一道Gmat数学题!For any positive integer n,the sum of the first n positive integers equals n(n+1)/2.what is the sum of all the even integers between 99 and 301?
结果1 题目 IfthesumofthefirstnpositiveintegersisS,whatisthesumofthefirstnpositiveevenintegers,intermsofS?() A. B. S C. 2S D. 2S2 E. 4S 相关知识点: 试题来源: 解析 C [解析]前n个正整数的和为:S=123…n前n个正偶数的和为:246…2n=2(123…n)=2S 反馈 收藏 ...
1What is the greatest commom divisor of positive integers m and n ?() (1)m is a prime number. (2)m and n are consecutive integers. A.条件(1)充分,但条件(2)不充分. B.条件(2)充分,但条件(1)不充分. C.条件(1)和(2)单独都不充分,但条件(1)和条件(2)联合起来充分. D.条件(1)...
Y = sum of the first 30 positive even integers Quantity A x-y Quantity B 30 A.Quantity A is greater. B.Quantity B is greater. C.The two quantities are equal. D.The relationship cannot be determined from the information given.
Answer to: Compute the sum of the first 50 positive integers that are exactly divisible by 5. By signing up, you'll get thousands of step-by-step...
回收铝; 玻璃; 塑料,纸,报纸,杂志; 电话簿和皱纸板。 [translate] aThen, use your result to find a formula for the sum of the first n positive integers. 然后,使用您的结果发现一个惯例为第一个n正面整数的总和。 [translate] 英语翻译 日语翻译 韩语翻译 德语翻译 法语翻译 俄语翻译 阿拉伯语翻译 ...