[解析] 当S<20时,S的取值范围较大,因此n的取值是不确定的,有好几个,所以(1)不充分;根据(2)同样无法得到确定的n值;根据(1)+(2)可得S的取值范围为[*],虽然S的值是不确定的,但只有当n=5时才满足上面的不等式,也即n的值惟一,所以(1)+(2)能充分地回答上面的问题。结果...
20 positive integers is 2870, What is the sum of the squares of the first 19 positive integers( ). A. 2350B. 2361C. 2470D. 2850相关知识点: 试题来源: 解析 C The sum of the squares of the first 20 positive integers is 2870, The sum of the squares of the first 19 is 2870−202...
The sum of the first k positive integers is equal to frack(k+1)2frack(k+1)2 . What is the sum of the integers from n to m, inclusive, where 0<n<m0<n<m ? 选项: A、 m(m+1)2−(n+1)(n+2)2m(m+1)2−(n+1)(n+2)2...
一道Gmat数学题!For any positive integer n,the sum of the first n positive integers equals n(n+1)/2.what is the sum of all the even integers between 99 and 301?
回收铝; 玻璃; 塑料,纸,报纸,杂志; 电话簿和皱纸板。 [translate] aThen, use your result to find a formula for the sum of the first n positive integers. 然后,使用您的结果发现一个惯例为第一个n正面整数的总和。 [translate] 英语翻译 日语翻译 韩语翻译 德语翻译 法语翻译 俄语翻译 阿拉伯语翻译 ...
1. for any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2. what is the sum of all the even integers between 99 and 301?A 10,100B 20,200C 22,650D 40,200E 45,150 答案 选择B解释:对任意整数n 前n项和是[n(n+1)]/2,求99到301之间所有偶数的和...
1. for any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2. what is the sum of all the even integers between 99 and 301?A 10,100B 20,200C 22,650D 40,200E 45,150 相关知识点: 试题来源: 解析 选择B解释:对任意整数n 前n项和是[n(n+1)]/2...
Now you are supposed to find the largest sum, together with the first and the last numbers of the maximum subsequence. Input Specification: Each input file contains one test case. Each case occupies two lines. The first line contains a positive integerK (≤). The second line containsK numbe...
Now you are supposed to find the largest sum, together with the first and the last numbers of the maximum subsequence. Input Specification: Each input file contains one test case. Each case occupies two lines. The first line contains a positive integerK (≤). The second line containsKnumbers...
For any positive integer n , the sume of the first n positive integers equal [n/(n+1)]/2.What is the sum of all the even integers between 99and 301? A10100 B 20200 C 22650 D 40200 E 45150 解答: 点赞0 阅读3547 解答: sysadmin老师 ...