n=int(input ()) sum=0 while n%2==0: sum=sum+n n=n-1 print(sum) 19th May 2020, 5:40 PM Satyam Patel 0 Hello everybody! Here is my code using while loop a=int(input()) b=0 c=0 while b<=a: c+=b b+=2 print(c) ...
循环语句 如果想把一个操作重复若干次,就要使用循环语句,存在两种循环语句:while循环和for循环。假设我们想生成一张2的乘法表, count = 1while count<= 10: table = 2 * count count = count +1 print(table) 1. for i in range(10): table = 2 * (i+1) print(table) 1. 条件语句 条件语句的用...
【题目】sum() python digit sum Awesome! Now let's try something a little trickier. Try summing th e digits o f a number.Instructions Writ e a function calle d digit sum that takes a positiv e integer n as input an d returns th e sum o f all that number's digits.For example: ...
You can do it mathematically if you convert the input to an int, and using the modulo operator to get the digit in the ones place (N % 10), then check that digit to see if it is even/odd Then use floor division to drop the digit from the ones place (N //= 10) and repeat un...
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whiletemp >0: digit = temp %10 sum += digit **3 The Python logic # Python program to check ifthe number provided by the userisan Armstrong numberornot # take input from the user num = int(input("Enter a number: ")) # initialise sum ...
();// Calculating the sum of integers a and bintsum=a+b;// Initializing a variable to count the number of digits in the sumintcount=0;// Counting the number of digits in the sum using a while loopwhile(sum!=0){sum/=10;++count;}// Displaying the digit number of the sum of ...
If you are using a while loop to add a number, {eq}increment {/eq}, every loop, this is essentially just multiplication. Letting the starting loop value be {eq}count_{s} {/eq} and the ending loop value be {eq}count_{e} {/eq}, the code becomes...
Python digit_sum Write a function calleddigit_sumthat takes a positive integernas input and returns the sum of all that number's digit. 第一种: def digit_sum(n): numbers = 0 number = str(n) for n in number: numbers += int(n)...