importjava.util.Scanner;publicclassSumOfDigits{//Method to calculate thesumof digits using awhileloop public staticintcalculateSum(intnumber){intsum=0;//Loop until the number becomes0while(number!=0){sum+=number%10;//Add the last digit tosumnumber=number/10;//Remove the last digit}returnsu...
A program to determine the sum of digits of a given non-negative integer number using a while loop is presented in Program. The program segment given below does the same thing using a do…while loop. 1 2 3 4 5 6 sum = 0; do { sum += num % 10; /* add LS d...
n=int(input ()) sum=0 while n%2==0: sum=sum+n n=n-1 print(sum) 19th May 2020, 5:40 PM Satyam Patel 0 Hello everybody! Here is my code using while loop a=int(input()) b=0 c=0 while b<=a: c+=b b+=2 print(c) ...
int SumOfDigits(int x) { int sum = 0; while (x != 0) { sum += x % 10; x /= 10; } return sum; } The helper function uses modula arithmetic to peel-off the last digit each time, then shift it down one place. Nice!
Alternatively, you can use awhileloop. #Sum all the Digits in a Number using awhileloop This is a three-step process: Initialize asumvariable to0. Use the modulo operator to get each digit of the number. Add each digit to thesumvariable. ...
It initializes an integer variable 'sum' to store the sum of the digits, starting with 0. It enters a while loop that continues as long as 'n' is not equal to 0. Inside the loop, it calculates the last digit of 'n' using the modulus operator (n % 10) and adds it to the 'su...
} while (inputOk == false); return n; } Feb 26, 2014 at 3:25am MiiNiPaa(8886) Nope, it won't work for numbers > 99. Your algorithm should be something like: 1) create accumulator variable and initialize it to 0 2) get last digit using (% 10) operation and add it to accumula...
[smaller_taken||digit<(k[where]-'0')],dp[sum][smaller_taken]);}}}dp=new_dp;}=(dp[0][false]+dp[0][true])%mod;--answer;if(answer==-1)answer=mod-1;cout<<answer<<"\n";}intmain(){ios::sync_with_stdio(false);cin.tie(0);// int t;// cin >> t;// while(t--)solve...
(n, sum);// returning sum for print} }intmain() { n = 1, sum = 0;while(n > 0) { cout <<"Enter a non-negative integer (enter 0 to end): \n"; cin >> n; sumDigits (n, sum);// calling sumDigitscout <<"The sum of all digits ", n," is: ", sum,"\n"; }return...
* Java method to return sum of digit using recursion * input 125 * output 8 */privatestaticintsumOfDigitUsingRecursion(intnumber,intsum) {if(number==0) {returnsum; } sum+=number%10;returnsumOfDigitUsingRecursion(number/10, sum);