那么nums中任意元素nums[i]来说,只要找出dp[0,sum(nums[0:i-1])] 中所有为1的元素,记为j,可以有dp[nums[i] + j] = 1 if dp[j] = 1。 代码如下: classSolution(object):defcanPartition(self, nums):""":type nums: List[int] :rtype: bool"""ifsum(nums) % 2 == 1:returnFalse nums...
每次遍历一遍DP,看sum/2处是否为true,为true时直接返回。 publicbooleancanPartition(int[]nums){if(nums==null||nums.length==0){returnfalse;}intsum=0;for(inti=0;i<nums.length;i++){sum+=nums[i];}if(sum%2==1){returnfalse;}boolean[]dp=newboolean[sum+1];dp[0]=true;for(intnum:nums)...
int sum = Arrays.stream(nums).sum(); // 场景1:和为奇数不能均分 if (sum % 2 == 1) { return false; } int target = sum / 2; int n = nums.length; boolean[][] dp = new boolean[n + 1][target + 1]; dp[0][0] = true; for (int i = 1; i <= n; i++) { for (...
Output: false Explanation: The array cannot be partitioned into equal sum subsets. Solution 0-1背包问题。 dp[j] = dp[j] || dp [j - n]; Code classSolution{public:boolcanPartition(vector<int>& nums){intsum =0;for(intn : nums) sum += n;if(sum %2!=0)returnfalse; sum /=2;re...
方案一:递归算法 假设原数组为nums,其中有n个数,其和为sum,那么需要在这n个数中找出一个子集使其和正好等于newSum(newSum = sum/2)。将此问...[LeetCode] 416. Partition Equal Subset Sum 题目内容 Given a non-empty array containing only positive integers, find if the array can be partitioned ...
Leetcode每日一题:416.partition-equal-subset-sum(分割等和子集),思路:这题从动态规划的思想上来看很像0-1背包问题,后者需要小于等于背包容量的条件下价值最大化,这里则是刚好等于数组之和的一半;1°,要想满足条件,数组之和sum必须为偶数,并且目标值target=sum/
if(sum&1)//奇数 return false; int n=nums.size(); int target=sum>>1; vector<vector<bool>> dp(n,vector<bool>(target+1)); if(nums[0]<=target){ dp[0][nums[0]]=true; } for(int i=1;i<n;i++){ for(int j=0;j<=target;j++){ ...
FindTabBarSize nums, returnif you can partition the array into two subsets such that the sum of the elements in both subsets is equal orfalseotherwise. Example 1: Input:nums = [1,5,11,5]Output:trueExplanation:The array can be partitioned as [1, 5, 5] and [11]....
LeetCode 416. Partition Equal Subset Sum Given anon-emptyarray containingonly positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Both the array size and each of the array element will not exceed 100. ...
Explanation: The array cannot be partitioned into equal sum subsets. 本题用DP来解。DP[i]表示是不是存在一个subset使得sum等于i. 1classSolution(object):2defcanPartition(self, nums):3"""4:type nums: List[int]5:rtype: bool6"""7s =sum(nums)89ifs % 2 == 1:returnFalse10target = s/21...