publicclassSolution{publicbooleancanPartition(int[] nums){// 数组求和intsum=Arrays.stream(nums).sum();// 场景1:和为奇数不能均分if(sum %2==1) {returnfalse; }inttarget=sum /2;intn=nums.length;boolean[][] dp =newboolean[n +1][target +1]; dp[0][0] =true;for(inti=1; i <= ...
publicbooleancanPartition(int[]nums){if(nums==null||nums.length==0){returnfalse;}intsum=0;for(inti=0;i<nums.length;i++){sum+=nums[i];}if(sum%2==1){returnfalse;}boolean[]dp=newboolean[sum+1];dp[0]=true;for(intnum:nums){for(inti=sum;i>=0;i--){if(dp[i]){dp[i+num]=...
https://leetcode.cn/problems/partition-equal-subset-sum 给你一个 只包含正整数 的 非空 数组 nums 。请你判断是否可以将这个数组分割成两个子集,使得两个子集的元素和相等。 示例1: 输入:nums = [1,5,11,5] 输出:true 解释:数组可以分割成 [1, 5, 5] 和 [11] 。 示例2: 输入:nums = [1,2...
Can you solve this real interview question? Partition Equal Subset Sum - Given an integer array nums, return true if you can partition the array into two subsets such that the sum of the elements in both subsets is equal or false otherwise. Example 1
https://discuss.leetcode.com/topic/46161/a-general-approach-to-backtracking-questions-in-java-subsets-permutations-combination-sum-palindrome-partitioning/2 里面比较难想的部分(对于我这种只捡easy模式的题目做的算法小白)是循环里面的递归,每次退栈的时候,会从cur中remove一个元素出来,然后i要加1,继续循环!
[leetcode]416. Partition Equal Subset Sum Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. 给定一个非空数组,是否能把数组划分为两个和相等的子集。 Not......
FindTabBarSize nums, returnif you can partition the array into two subsets such that the sum of the elements in both subsets is equal orfalseotherwise. Example 1: Input:nums = [1,5,11,5]Output:trueExplanation:The array can be partitioned as [1, 5, 5] and [11]....
Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in b...
Leetcode每日一题:416.partition-equal-subset-sum(分割等和子集),思路:这题从动态规划的思想上来看很像0-1背包问题,后者需要小于等于背包容量的条件下价值最大化,这里则是刚好等于数组之和的一半;1°,要想满足条件,数组之和sum必须为偶数,并且目标值target=sum/
Code classSolution{public:boolcanPartition(vector<int>& nums){intsum =0;for(intn : nums) sum += n;if(sum %2!=0)returnfalse; sum /=2;returnsubsetsum(nums, sum); }boolsubsetsum(vector<int>& nums,intsum){intdp[sum +1] = {false}; ...