Given an integer arraynumsand an integerk, returnthe length of the shortest non-emptysubarrayofnumswith a sum of at leastk. If there is no suchsubarray, return-1. Asubarrayis acontiguouspart of an array. Example 1: Input:nums = [1], k = 1Output:1 Example 2: Input:nums = [1,2]...
int getLongestSubarry(vector<int> &vec, int k){ int sum=0, res=0; map<int, int> sum_map; for(int idx=0; idx<vec.size(); ++idx){ sum += vec[idx]; if(sum<=k) res = idx+1; //此处修改 else { //前n项和大于sum-k并且需要最早的,此时子数组长度最长 map<int,int>::iterat...
public int numSubarraysWithSum(int[]A,intS) { return atMost(A,S) - atMost(A,S- 1); } private int atMost(int[]A,intS) { if (S< 0) return 0; int res = 0, n =A.length; for (inti= 0,j= 0;j<n; ++j) {S-=A[j]; while (S< 0)S+=A[i++]; res += j - i...
leetcode 930. Binary Subarrays With Sum This remains me of some 'subarray count' type problems….. classSolution{publicintnumSubarraysWithSum(int[] A,intS){int[] ps =newint[A.length +1]; ps[0] =1;intsum=0;intret=0;for(intv: A) { sum += v;if(sum - S >=0) { ret +=...
numsand an integerthe number of non-emptysubarrayswith a sumgoal. Asubarrayis a contiguous part of the array. Example 1: Input:nums = [1,0,1,0,1], goal = 2Output:4Explanation:The 4 subarrays are bolded and underlined below:
209. Minimum Size Subarray Sum 长度最小的子数组 Title给定一个含有 n 个正整数的数组和一个正整数 s ,找出该数组中满足其和 ≥ s 的长度最小的连续子数组,并返回其长度。如果不存在符合条件的连续子数组,返回 0。**示例: **输入: s = 7, nums = [2,3,1,2,4,3]输出: 2解释: 子数组 [4,3...
public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; for (int i = 1; i < A.length; i++) { ...
Shortest Subarray with Sum at Least K - Python 问题描述: 和至少为 K 的最短子数组 返回 A 的最短的非空连续子数组的长度,该子数组的和至少为 K 。 如果没有和至少为 K 的非空子数组,返回 -1 。 示例 1: 示例 2: 示例 3: 提示: 1 <= A.length <= 50000 -10 ^ 5 <= A[i] <=.....
C++ implementation to find subarray with given sum#include <bits/stdc++.h> using namespace std; vector<int> find(vector<int> a,int n,int s){ vector<int> b; //output vector int cur_sum=0; for(int i=0;i<n;i++){ cur_sum=a[i];//cur_suming element for(int j=i+1;j<n;j...
2.Smallest Subarray with a given sum(easy) 2.1 问题描述 2.2 解决方法 2.3 代码 3.课后回顾 4.参考链接 sliding window pattern 1.原理描述 滑动窗口模式(sliding window pattern)是用于在给定数组或链表的特定窗口大小上执行所需的操作,比如寻找包含所有 1 的最长子数组。从第一个元素开始滑动窗口并逐个元素...