Leetcode: Subarray Sum Equals K\\\Binary Subarrays With Sum Problem Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k. Example 1: Input: nums = [1,1,1], k = 2 Output: 2 Note: The length......
Leetcode 53. Maximum Subarray 2. Solution **解析:**Version 1,简单粗暴,前i个元素总和大于0,则这些元素对总和是有贡献的,要保留,否则,则丢弃前i个元素。重新开始执行上述操作,每次加完记得更新最大值。Version 2,采用动态规划求解,首先定义状态,dp[i]是以nums[i]为结尾的连续子数组的最大和,状态转移方程...
209. Minimum Size Subarray Sum java solutions Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead. For example, given the array[2,3,1,2,4,3]ands = 7, the subarray[4,...
1 class Solution { 2 public int minSubArrayLen(int s, int[] nums) { 3 if (nums == null || nums.length == 0) { 4 return 0; 5 } 6 int N = nums.length; 7 int min = Integer.MAX_VALUE; 8 int left = 0; 9 int sum = 0; 10 11 for(int i = 0; i < N; i++) { ...
import java.util.HashMap; class Solution { public int subarraySum(int[] nums, int k) { HashMap<Integer,Integer> prefixSum = new HashMap<>(); prefixSum.put(0,1); int sum = 0, count = 0; for(int i=0; i<nums.length; i++){ ...
问题描述: Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contai... leetcode 之4Sum问题 ...
You may assume the sum of all the numbers is in the range of a signed 32-bit integer. Solution class Solution { public boolean checkSubarraySum(int[] nums, int k) { if (nums == null || nums.length < 2) return false; if (k == 0) { ...
leetcode 560. Subarray Sum Equals K technically, no different with two sum...560. Subarray Sum Equals K Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k. Example 1: Note: The length of the array is in ...
Java AI检测代码解析 class Solution { public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; ...
遍历map,如果有value>1的,则存在,返回true,否则返回false; Runtime:1 ms, faster than96.91%of Java online submissions for Find Subarrays With Equal Sum. Memory Usage:40.1 MB, less than86.76%of Java online submissions for Find Subarrays With Equal Sum....