int getLongestSubarry(vector<int> &vec, int k){ int sum=0, res=0; map<int, int> sum_map; for(int idx=0; idx<vec.size(); ++idx){ sum += vec[idx]; if(sum<=k) res = idx+1; //此处修改 else { //前n项和大于sum-k并且需要最早的,此时子数组长度最长 map<int,int>::iterat...
2.Smallest Subarray with a given sum(easy) 2.1 问题描述 2.2 解决方法 2.3 代码 3.课后回顾 4.参考链接 sliding window pattern 1.原理描述 滑动窗口模式(sliding window pattern)是用于在给定数组或链表的特定窗口大小上执行所需的操作,比如寻找包含所有 1 的最长子数组。从第一个元素开始滑动窗口并逐个元素...
1publicclassSubarrayWithGivenSum {2publicstaticint[] findSubarrayWithGivenSum(int[] arr,intsum) {3int[] range =newint[2];4range[0] = -1; range[1] = -1;5if(arr ==null|| arr.length == 0 || sum < 0) {6returnrange;7}8intstart = 0;9intcurrSum = arr[0];10for(intend = ...
{ start, end }; } } } return new int[] { -1, -1 }; // Return -1 if no subarray is found } public static void main(String[] args) { int[] arr = { 1, 2, 3, 7, 5 }; int targetSum = 12; int[] result = findSubarrayWithGivenSum(arr, targetSum); if (result[0] !
C++ implementation to find subarray with given sum#include <bits/stdc++.h> using namespace std; vector<int> find(vector<int> a,int n,int s){ vector<int> b; //output vector int cur_sum=0; for(int i=0;i<n;i++){ cur_sum=a[i];//cur_suming element for(int j=i+1;j<n;j...
ineditorial. Then I came up with a different approach: we can iterate through the possible length of a subarray, pick one with the largest sum, update the answer. However, I don't know how to implement finding a subarray with length = 1..n and maximum sum fast enough to pass all ...
Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K. Example 1: Input: A = [4,5,0,-2,-3,1], K = 5 Output: 7 Explanation: There are 7 subarrays with a sum divisible by K = 5: ...
Given a binary array arr[] and an integer target, return the number of non-empty subarrays with a sum equal to the target. Note: A subarray is the contiguous part of the array. Examples: Input: arr[] = [1, 0, 1, 0, 1], target = 2 ...
Given an integer array, find a subarray with sum closest to zero. Return the indexes of the first number and last number. Example Given [-3, 1, 1, -3, 5], return [0, 2], [1, 3], [1, 1], [2, 2] or [0, 4].
Given an integer array, find a subarray where the sum of numbers iszero. Your code should return the index of the first number and the index of the last number. Notice: There is at least one subarray that it's sum equals to zero. ...