int getLongestSubarry(vector<int> &vec, int k){ int sum=0, res=0; map<int, int> sum_map; for(int idx=0; idx<vec.size(); ++idx){ sum += vec[idx]; if(sum<=k) res = idx+1; //此处修改 else { //前n项和大于sum-k并且需要最早的,此时子数组长度最长 map<int,int>::iterat...
2.Smallest Subarray with a given sum(easy) 2.1 问题描述 Given an array of positive integersnumsand a positive integertarget, return the minimal length of a「contiguous subarray」[numsl, numsl+1, ..., numsr-1, numsr]of which the sum is greater than or equal totarget. If there is no...
Leetcode: Subarray Sum Equals K\\\Binary Subarrays With Sum Problem Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k. Example 1: Input: nums = [1,1,1], k = 2 Output: 2 Note: The length......
1publicclassSubarrayWithGivenSum {2publicstaticint[] findSubarrayWithGivenSum(int[] arr,intsum) {3int[] range =newint[2];4range[0] = -1; range[1] = -1;5if(arr ==null|| arr.length == 0 || sum < 0) {6returnrange;7}8intstart = 0;9intcurrSum = arr[0];10for(intend = ...
C++ implementation to find subarray with given sum #include<bits/stdc++.h>usingnamespacestd;vector<int>find(vector<int>a,intn,ints){vector<int>b;//output vectorintcur_sum=0;for(inti=0;i<n;i++){cur_sum=a[i];//cur_suming elementfor(intj=i+1;j<n;j++){//add next element conti...
Can you solve this real interview question? Binary Subarrays With Sum - Given a binary array nums and an integer goal, return the number of non-empty subarrays with a sum goal. A subarray is a contiguous part of the array. Example 1: Input: nums =
Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K. Example 1: Input: A = [4,5,0,-2,-3,1], K = 5 Output: 7 Explanation: There are 7 subarrays with a sum divisible by K = 5: ...
Given an integer array, find a subarray with sum closest to zero. Return the indexes of the first number and last number. Example Given [-3, 1, 1, -3, 5], return [0, 2], [1, 3], [1, 1], [2, 2] or [0, 4].
Write a Scala program to find minimum subarray sum of specified size in a given array of integers. Example: Input: nums = { 1, 2, 3, 4, 5, 6, 7, 8, 9,10} Output: Sub-array size: 4 Sub-array from 0 to 3 and sum is: 10 ...
/**Key point: if we can find any two subarray of prefix sum have same mod value, then their difference MUST be * divisible by k. So we can use a map to store mod value of each prefix sum in map, with its index. Then check ...